c - strstr() 不适用于 C

Question

我有下面的代码。问题是当我运行它时，它没有显示我提示的搜索；在 for 中尝试 printf("%s", strstr(tracks[i], search_for)) 返回 null，但是对 tracks 做同样的事情没有问题[i] 和 search_for。请帮忙!

#include <stdio.h>
#include <string.h>

char tracks[][80]={
  "I left my heart in Harvard Med Scholl",
  "Newark, Newark - a wonderful town",
  "Dancing with a Dork",
  "From here to maternity",
  "The girl from Iwo Jima",
};

void find_track(char search_for[]){
  int i;
  for(i=0; i<5; i++){
    if(strstr(tracks[i], search_for)){
      printf("Track %i: '%s'\n", i, tracks[i]);
    }
  }
};

int main(){

  char search_for[80];
  printf("Search for: ");
  fgets(search_for, 80, stdin);
  find_track(search_for);
  return 0;
}

Answer 1

正如我们在 fgets() 中看到的那样文档，如果行末有换行符，它将包含在生成的字符串中:

Reads at most count - 1 characters from the given file stream and stores them in str. The produced character string is always NULL-terminated. Parsing stops if end-of-file occurs or a newline character is found, in which case str will contain that newline character.

所以在这种情况下，如果我们输入 "Newark"，那么我们有:

search_for[] = {'N', 'e', 'w', 'a', 'r', 'k', '\n', '\0', ...};

您需要删除多余的换行符。