linux - 循环 Bash Shell 脚本

Question

我几乎是 linux 的新手，我编写了一个简单的 bash shell 脚本，它要求用户输入一个数字，然后再询问另一个数字并显示数字的总和和乘积。我对此没有问题，但我想循环脚本。

例如，我想询问用户是否要退出，如果他们选择不退出，脚本会重新开始并再次询问两个数字。如果有人在那里知道循环的东西，你能帮我吗？谢谢。

这是我的代码:

#!/bin/bash


echo -n "Name please? "
read name
echo "enter a number."
read number1
echo "enter another number"
read number2
echo "Thank you $name"
let i=0
let i=$number1+$number2
let x=0 
let x=$number1*$number2
echo "The sum of the two numbers is: $i"
echo "The product of the two numbers is: $x"
echo "Would you like to quit? Y/N? "
quit=N
while [ "$quit" = "Y" ]
do 
  clear  
  while ["$quit" != "Y" ]
  do
    echo "enter a number."
    read number1
    echo "enter another number"
    read number2
    echo "Thank you $name"
    let i=0
    let i=$number1+$number2
    let x=0 
    let x=$number1*$number2
    echo "The sum of the two numbers is: $i"
    echo "The product of the two numbers is: $x"
    echo "Would you like to quit? Y/N? "

Answer 1

#!/bin/bash

# Initialize quit so we enter the outer loop first time
quit="N"

# Loop while quit is N
while [ "$quit" = "N" ]
do
  echo -n "Name please? "
  read name
  echo "enter a number."
  read number1
  echo "enter another number"
  read number2
  echo "Thank you $name"
  let i=0
  let i=$number1+$number2
  let x=0 
  let x=$number1*$number2
  echo "The sum of the two numbers is: $i"
  echo "The product of the two numbers is: $x"

#reset quit - so we enter the inner loop first time
  quit="" 

#we want to repeat until quit is Y or N: 
#while quit is not "Y" and quit is not "N"
  while [ "$quit" != "Y" -a "$quit" != "N" ]
  do
    echo "Would you like to quit? Y/N?"
    read quit

#Convert lower case y/n to Y/N
    quit=`echo $quit | tr yn YN`
  done
done