linux - awk，从最后一列到\r\n (CRNL)

Question

我有一个包含如下行的文件:

Internet Protocol Version 4, Src: 192.168.0.29 (192.168.0.29), Dst: www.l.google.com (64.233.187.104)
    Time to live: 128
    User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.7.5) Gecko/20041107 Firefox/1.0\r\n

如果我使用 $NF，我会得到:

rv:1.7.5)

但我想要:

Firefox/1.0

我想制作我的脚本，如下所示:

awk '
    /    User-Agent/{brow=$NF}
    END{
        print brow;
    }
'

如有任何建议，我们将不胜感激!

完整脚本:(固定)

#!/bin/bash
echo $1;
awk '/    User-Agent/{print}' $1 > useragents_$1;
echo '----------------------------------------------------' >> useragents_$1;
sort useragents_$1 | uniq >> useragents_$1;
awk '
    /Internet Protocol Version 4, Src:/{ip=$(NF-4)}
    /    Time to live/{ttl++}
    /    Time to live/{sttl=$NF}
    /    User-Agent/{os=$(NF-6)" "$(NF-5)}
    /    User-Agent/{brow=$NF}
    /    User-Agent/{agent++}
    /    User-Agent/{stringtemp=sttl"\t"ip"\t"os"\t"brow}
    /Windows/{windows++}
    /Linux/{linux++}
    /Solaris/{solaris++}
    END{
        sub(/\\r.*$/, "", brow);
        print "TTL\tIP\t\tOS\t\tBROWSER";
        print stringtemp;
        print "\nSUMMARY";
        print "\tttl\t=\t"ttl; print "\twindows\t=\t"windows;
        print "\tlinux\t=\t"linux; print "\tsolaris\t=\t"solaris;
        print "\tagent\t=\t"agent
    }
' $1 > useragents_$1;
more useragents_$1;

输出:

examplehttppacket.txt
TTL     IP              OS              BROWSER
128     192.168.0.29    Windows NT      Firefox/1.0\r\n

SUMMARY
        ttl     =       1
        windows =       3
        linux   =
        solaris =
        agent   =       1

感谢大家的帮助，看来主要是文本文件的问题!

Answer 1

这个 awk 应该可以工作:

awk '/User-Agent/{brow=$NF} END{sub(/\\r.*$/, "", brow); print brow;}' file