linux - 这些输出是什么意思？

Question

尤其是最后两个分别带有'-'和'+'，这到底是什么意思？

[1]   Done                    php start.php bots/admin32.bot.php

[2]   Done                    php start.php bots/admin36.bot.php

[3]   Done                    php start.php bots/admin10.bot.php

[4]   Done                    php start.php bots/admin11.bot.php

[5]   Done                    php start.php bots/admin13.bot.php

[6]   Done                    php start.php bots/admin3.bot.php

[7]-  Done                    php start.php bots/admin4.bot.php

[8]+  Done                    php start.php bots/admin7.bot.php

[root@www2 robot]# 

Answer 1

来自Bash Reference Manual ,

Job number n may be referred to as ‘%n’. The symbols ‘%%’ and ‘%+’ refer to the shell's notion of the current job, which is the last job stopped while it was in the foreground or started in the background. A single ‘%’ (with no accompanying job specification) also refers to the current job. The previous job may be referenced using ‘%-’. If there is only a single job, ‘%+’ and ‘%-’ can both be used to refer to that job. In output pertaining to jobs (e.g., the output of the jobs command), the current job is always flagged with a ‘+’, and the previous job with a ‘-’.

在启动和停止作业时 Bash 的输出中，

[n]+ status

表示“工作%n(也称为工作%+)现在是状态”。