linux - 将 Perl 命令输出到 shell 变量中

Question

我对 Perl 有点菜鸟，看不出这个脚本有什么问题:

#!/bin/sh
randAnPass=true;
if [ $randAnPass = true ]
then
pass=perl /root/bin/randpass
else
# prompt for setting user's password ..
echo -n "pick password for '${user}': "
read pass
fi
#echo $randAnPass;
echo "Generated pass = $pass";

出于某种原因它输出:

r4Nd0mP
Generated pass = 

我要输出

Generated pass = r4Nd0mP

Answer 1

如果你想只捕获标准输出 perl 命令的使用，

pass=$(perl /root/bin/randpass)

但是如果你需要同时捕获STDERR和STDOUT，

pass=$(perl /root/bin/randpass 2>&1)