c++ - 将字符串文字分配给 char*

Question

以下代码在 C++0x 中是合法的、弃用的还是非法的？

char* p = "foobar";

我最初问这个问题 here作为评论。

Answer 1

转换

char* p = "foobar";

在 C++98/C++03 中被弃用，并在 C++0x 中被移除(即，§4.2/2 被移除)。

因此，该代码在 C++0x 中无效。

但是，MinGW g++ 4.4.1 仍然只发出警告，不发出错误。

C++98/C++03 §4.2/2 (which is removed in C++0x):

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A string literal (2.13.4) that is not a wide string literal can be converted to an rvalue of type “pointer to char”; a wide string literal can be converted to an rvalue of type “pointer to wchar_t”. In either case, the result is a pointer to the first element of the array. This conversion is considered only when there is an explicit appropriate pointer target type, and not when there is a general need to convert from an lvalue to an rvalue. [Note: this conversion is deprecated. See Annex D. ] For the purpose of ranking in overload resolution (13.3.3.1.1), this conversion is considered an array-to-pointer conversion followed by a qualification conversion (4.4). [Example: "abc" is converted to “pointer to const char” as an array-to-pointer conversion, and then to “pointer to char” as a qualification conversion. ]