ios - NSURL 不转换安全字符串

Question

我想发送带get参数的url:

let customAllowedSet =  NSCharacterSet(charactersInString:"=\"#%/<>?@\\^`{|}&").invertedSet

guard let safeUrl = "\(GVariables.Url)?id=\(self.UUID)&device_name=\(UIDevice.currentDevice().name)&email=\(email)&first_name=\(firstName)&last_name=\(lastName)".stringByAddingPercentEncodingWithAllowedCharacters(customAllowedSet) else {
       return
     }
     print(safeUrl)
     guard let url = NSURL(string: safeUrl) else {
          return
     }
     print(url)

输出是:

http:%2F%2Fmyurl.com:8000%2Fs%2F%3Fid%3D15FDA6B3-C51A-4057-8F98-0143981CC5C8%26device_name%3DArtem's iPhone%26email%3D%26first_name%3D%26last_name%3D

但转换为 NSURL 总是返回 nil。

Answer 1

您用于对 URL 进行编码的自定义字符集可能看起来很高效，但它并不完整。

例如，在您的情况下，它缺少对空格字符“”的编码。

最好改用已知的方法:

yourStringURL.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLFragmentAllowedCharacterSet())