ios - 如何使用 Segue 从 didFinishPickingMediaWithInfo 发送 UIImage？

Question

所以我有:

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info:[String : Any]) {
    let tempImage: UIImage = info[UIImagePickerControllerOriginalImage] as! UIImage
    let imagetoTransmit: UIImage = tempImage
    shootedImage = imagetoTransmit
    self.performSegue(withIdentifier: "cameraSegueIdent", sender: nil)
    dismiss(animated: true, completion: nil)
}

哪里继续:

 override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "cameraSegueIdent" {
        let imageToTransmit: UIImage = shootedImage
        let viewController = (segue.destination as! TakenPhotoPreviewViewController)
        viewController.takenImage = imageToTransmit
    } 
}

正在发送图像，但 Segue 不执行。
请帮忙!

更新

我的想法是将图像作为发件人发送，而不保存在当前的 ViewController 中，而且效果非常好!

  func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info:[String : Any]) {

    let tempImage: UIImage = info[UIImagePickerControllerOriginalImage] as! UIImage
    self.dismiss(animated: true) {
    self.performSegue(withIdentifier: "cameraSegueIdent", sender: tempImage)
    }
}

Answer 1

以下内容可能会有所帮助。

    let tempImage: UIImage = info[UIImagePickerControllerOriginalImage] as! UIImage
    let imagetoTransmit: UIImage = tempImage
    shootedImage = imagetoTransmit
    _ picker.dismissViewControllerAnimated(true, completion: {
        self.performSegue(withIdentifier: "cameraSegueIdent", sender: nil)
    })

此外，请确保在您的 Storyboard中正确配置了 segue 标识符。