javascript - img 缩略图单击用缩略图标题替换 div 文本值

Question

JSFIDDLE HERE

如果您查看 js fiddle，您会发现单击缩略图会更改图像以及 .currentimgtitle 文本值，但它会更改所有 .currentimgtitle 文本值当我只想更改与其相关的页面时，jquery 和 html 在下面

$(".imgcontainer").each(function() {
    var imgsrc = $(".minicontainer img:first-child", this).attr("src");
    var imgtitle = $(".minicontainer img:first-child", this).attr("title");
    $(this).append('<div class="presentouter"><img src="' + imgsrc + '" class="presentimg"/><div class="currentimgtitle" title="' + imgtitle + '">' + imgtitle + '</div></div>');
});
$(".miniimg, .miniimg2, .miniimg3").click(function() {
    var miniimgrc = $(this).attr("src"),
        $presentImg = $(this).closest(".imgcontainer").find(".presentimg");

    $presentImg.attr('src', miniimgrc);
});
$(".miniimg, .miniimg2, .miniimg3").click(function(index) {
    var miniimgtitle = $(this).attr("title"),
        $presentTitle = $(this).closest(".imgcontainer").find(".currentimgtitle");

    $presentTitle.attr('title', miniimgtitle);

});
$(".imgcontainer").each(function(index) {
$(".miniimg, .miniimg2, .miniimg3").click(function() {
    var textval =  $(this).attr("title");
    $(".currentimgtitle").text(textval);
});
});
<div class="imgcontainer">
    <div class="minicontainer">
    <img src="http://lh3.googleusercontent.com/_Zuzii37VUO4/Ta0nUeMwXoI/AAAAAAAAFoc/7f0Um7OTgNg/s000/Antartic-by-Peter-Rejcek.jpg" title="icy mountains" class="miniimg"/>
    <img src="http://lh3.googleusercontent.com/_Zuzii37VUO4/Ta0nUFUhg6I/AAAAAAAAFoY/GToUxRYcteY/s000/Antartic-by-Kelly-Speelman.jpg" title="icy planes and hills" class="miniimg2"/>
    <img src="http://lh4.googleusercontent.com/_Zuzii37VUO4/Ta0nTs8AbPI/AAAAAAAAFoU/zCvNKv4kfe4/s000/BeachWaves-By-RePublicDomain.jpg" title="sun rise with clouds" class="miniimg3"/>
    </div>
</div>

<div class="imgcontainer">
    <div class="minicontainer">
    <img src="http://3.bp.blogspot.com/-EyJOI3UFWvo/Te5KHGgOpSI/AAAAAAAAESY/PhG66jWB1OA/s200/blogger-featured-slideshow.png" title="Blogger Logo" class="miniimg"/>
    <img src="http://2.bp.blogspot.com/-BKPnpE6QpfY/TewL7Q16ipI/AAAAAAAAERg/pxn6NY1nNsg/s640/best-blogger-template-stunning-slider-magazine.PNG" title="blogger template" class="miniimg2"/>
    <img src="http://4.bp.blogspot.com/-gxaZr19LXtY/TdRcJrxv3gI/AAAAAAAAD68/KaX9UN0B2nE/s640/advanced-design-magazine-blogger-template.PNG" title="another blogger template" class="miniimg3"/>
    </div>
</div>

Answer 1

虽然我看到您已经接受了答案，但这种方法似乎效果很好:

$('.minicontainer img').click(
    function(){
        var miniImgSrc = this.src,
            imgTitle = this.title,
            $container = $(this).closest('.imgcontainer');
        $container
            .find('.presentimg')
            .attr('src',miniImgSrc);
        $container
            .find('.currentimgtitle')
            .attr('title',imgTitle)
            .text(imgTitle);
    });

JS Fiddle demo .

引用资料:

• attr() .
• .closest() .
• find() .
• text() .
• element.title .