javascript - 为什么我无法读取传递给函数的对象的属性？在 JavaScript 中

Question

我在函数 getOlder() 中遇到下一个错误:
类型错误:无法读取未定义的属性“年龄”

问题是什么以及如何解决？

function person(name, age) {
    this.name=name;
    this.age=age
}

// Returns the older person in a group of persons.
var getOlder = function(people) {
    if (people.length === 0) {
        return new person();
    }

    var older = people[0]; // The first one is the older for now.

    var value;
    for (var _ in people) {
        value = people[_];
        if (value.age > older.age) {
            older = value;
        }
    }
    return older;
};

// Declare some persons.
var paul = new person("Paul", 23);
var jim = new person("Jim", 24);
var sam = new person("Sam", 84);
var rob = new person("Rob", 54);
var karl = new person("Karl", 19);

var older = getOlder(paul, jim);
if (older.name !== "Jim") {
    console.log("Fail");
}

Answer 1

查看函数的签名:

var getOlder = function(people) {

您没有创建接受两个人对象的函数。您显然只接受一个数组，因为您在函数内部使用 people.length 和 people[0]。所以你还必须传递一个数组:

var older = getOlder([paul, jim]);