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android - okhttp 响应中的新 JsonObject

转载 作者:塔克拉玛干 更新时间:2023-11-02 22:42:24 24 4
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我正在尝试使用OKHttphttps://github.com/hongyangAndroid/okhttp-utils来实现登录功能,但我不知道如何实现创建新的 JsonObject 在回调中使用 Response。

  OkHttpUtils.post()
.url(url)
.addParams("phone", "18681873411")
.addParams("password", "18681873411")
.build()
.execute(new Callback() {
@Override
public Object parseNetworkResponse(Response response) throws Exception {
Log.i("ws","---->>parseNetworkResponse" + response.body().string());


JSONObject jsonObj = null;
try {
jsonObj = new JSONObject(response.body().string());
} catch (JSONException e) {
Log.i("ws","---->>JSONException");
e.printStackTrace();
} catch (IOException e) {
Log.i("ws","---->>IOException");
e.printStackTrace();
}
Log.i("ws","---->>111 :" );
String opCode = jsonObj.getString("OpCode");
String message = jsonObj.getString("Message");
Log.i("ws","---->>111 opCode:" + opCode);
Log.i("ws","---->>111 Message:" + message);
JSONObject result = new JSONObject();
result.put("qrcode",opCode);
result.put("message", message);
return result;

}

@Override
public void onError(Call call, Exception e) {
Log.i("ws","---->>onError" + e);
}

@Override
public void onResponse(Object response) {
Log.i("ws","---->>onResponse" + response.toString());
}
});

及错误信息:

parseNetworkResponse{"OpCode":0,"Message":"登陆成功","Other":{"id":1,"name":null,"phone":"18681873411","QQuid":null,"weixinuid":null,"gender":null,"age":null,"credits":null,"address":null,"signature":null,"imageurl":null,"password":"18681873411","created_at":"2016-05-19T17:05:02.000Z","updated_at":"2016-05-19T17:05:02.000Z"}}
05-20 11:29:01.953 13496-13621/com.smartspace.magicmirror I/ws: ---->>IOException
05-20 11:29:01.954 13496-13621/com.smartspace.magicmirror I/ws: ---->>111 :
05-20 11:29:01.955 13496-13496/com.smartspace.magicmirror I/ws: ---->>onErrorjava.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String org.json.JSONObject.getString(java.lang.String)' on a null object reference

最佳答案

由于调用 response.body().string() 会从返回流中读取内容然后关闭它,所以第二次调用它。它不会返回任何内容:\

更好的方法:

if (!response.isSuccessful()) throw new IOException("Unexpected code " + response); 
String responseData = response.body().string();
Log.e(TAG, "onResponse: " + responseData);
try {
JSONObject jsonObject = new JSONObject(responseData);
// Do something here
} catch (JSONException e) {
...}

关于android - okhttp 响应中的新 JsonObject,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37337516/

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