javascript - 如何在子窗口的父窗口中运行脚本？

Question

我的 child.html 有一个按钮，可以使用脚本 $('[value="Submit"]').click();我想从 parent.html

调用它

像这样:

var popUp = window.open('https://child.html');
popUp.$('[value="Submit"]').click();//这一行应该修复

怎么会这样？

Answer 1

你应该使用 window.postMessage应用程序接口(interface)。这是示例代码。

child.html

function functionToBeExecuted(event)
{
  // do click or whatever you want
}

window.addEventListener("message", functionToBeExecuted, false);

parent.html

let child = window.open('child.html');

child.postMessage(); // notice that I did not pass message argument, since you just want to trigger the function, but if you want to pass some data to function using event parameter, just pass data to this function (for example string or object etc.)