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php - 使用 JSON 从 Android 发送 Base64 图像到 php webservice,解码,保存到 SQL

转载 作者:塔克拉玛干 更新时间:2023-11-02 22:37:48 24 4
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正如描述所说,我正在用 Android 拍照。它被压缩并添加到 byte[] 然后 base64encoded。它使用 JSON 发送到我的网络服务,在那里它“应该”被解码并保存在 SQL 表行 中。我可以将编码后的字符串保存在单独的行中,这样我就知道它到达那里了。

任何人都可以看看这个并告诉我哪里做错了吗? *抱歉代码太长。如果有人提供帮助,我不想错过任何东西!

安卓端

@Override
protected String doInBackground(String... args) {
// TODO Auto-generated method stub
// Check for success tag

int success;
stream = new ByteArrayOutputStream();
picture.compress(Bitmap.CompressFormat.JPEG, 50, stream);
image = stream.toByteArray();

String ba1 = Base64.encodeToString(image, Base64.DEFAULT);

SharedPreferences sp = PreferenceManager.getDefaultSharedPreferences(MainScreen.this);
String post_username = sp.getString("username", "anon");

try {
ArrayList<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", post_username));
params.add(new BasicNameValuePair("picture", ba1));

JSONObject json = jsonParser.makeHttpRequest(POST_COMMENT_URL,
"POST", params);


success = json.getInt(TAG_SUCCESS);
if (success == 1) {
Log.d("Picture Added!", json.toString());
//finish();
return json.getString(TAG_MESSAGE);
} else {
Log.d("Upload Failure!", json.getString(TAG_MESSAGE));
return json.getString(TAG_MESSAGE);

}
} catch (JSONException e) {
e.printStackTrace();
}

return null;

}

protected void onPostExecute(String file_url) {
// dismiss the dialog once product deleted
pDialog.dismiss();
if (file_url != null) {
Toast.makeText(MainScreen.this, file_url, Toast.LENGTH_LONG)
.show();
}

}
}

}

PHP 端

<?php
require("config.inc.php");
if (!empty($_POST)) {
$user = $_POST['username'];
$data = $_POST['picture'];
$data = base64_decode($data);
$im = imagecreatefromstring($data);
header('Content-Type: image/jpeg', true);
ob_start();
imagejpeg($im);
$imagevariable = ob_get_contents();
ob_end_clean();

$query = "INSERT INTO pictures ( username, photo, rawdata ) VALUES ( :user, :photo, :raw ) ";

$query_params = array(
':user' => $user,
':photo' => $imagevariable,
':raw' => $_POST['picture']
);

try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error. Couldn't add post!";
die(json_encode($response));
}
$response["success"] = 1;
$response["message"] = "Picture Successfully Added!";
echo json_encode($response);

} else {
}
?>

最佳答案

我想发布我的解决方案,以防其他人遇到此问题。我总是来 S.O.寻求答案,所以现在轮到我帮助别人了。我在使用位图时遇到内存不足错误的问题。我将其更改为多部分帖子,以将图片作为文件和字符串(如他们的名字)上传,但您可以向其中添加任何字符串。第一部分是 android 端,下面是数据库的 php。使用移动文件方法将图片添加到目录中的文件中。数据库存储该图片的路径。我搜索了两天,从堆栈溢出帖子中拼凑起来。

安卓

public void onClick(View v) {
if (v.getId() == R.id.capture_btn) {
try {

Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
startActivityForResult(intent, CAMERA_IMAGE_CAPTURE);

} catch (ActivityNotFoundException anfe) {

String errorMessage = "Whoops - your device doesn't support capturing images!";
Toast toast = Toast.makeText(this, errorMessage,
Toast.LENGTH_SHORT);
toast.show();

}

}
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == CAMERA_IMAGE_CAPTURE
&& resultCode == Activity.RESULT_OK) {
getLastImageId();

new PostPicture().execute();
}
}

private int getLastImageId() {
// TODO Auto-generated method stub
final String[] imageColumns = { MediaStore.Images.Media._ID,
MediaStore.Images.Media.DATA };
final String imageOrderBy = MediaStore.Images.Media._ID + " DESC";
Cursor imageCursor = managedQuery(
MediaStore.Images.Media.EXTERNAL_CONTENT_URI, imageColumns,
null, null, imageOrderBy);
if (imageCursor.moveToFirst()) {
int id = imageCursor.getInt(imageCursor
.getColumnIndexOrThrow(MediaStore.Images.Media._ID));
fullPath = imageCursor.getString(imageCursor
.getColumnIndex(MediaStore.Images.Media.DATA));
Log.d("pff", "getLastImageId: :id " + id);
Log.d("pff", "getLastImageId: :path " + fullPath);
return id;

} else {
return 0;
}
}

class PostPicture extends AsyncTask<String, String, String> {

@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(MainScreen.this);
pDialog.setMessage("Uploading Picture");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();

}

@Override
protected String doInBackground(String... args) {
// TODO Auto-generated method stub
// Check for success tag

HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://www.your-php-page.php");

try {

MultipartEntity entity = new MultipartEntity(
HttpMultipartMode.BROWSER_COMPATIBLE);
File file = new File(fullPath);
cbFile = new FileBody(file, "image/jpeg");
Log.d("sending picture", "guest name is " + guest_name);
Log.d("Sending picture", "guest code is " + guest_code);
entity.addPart("name",
new StringBody(guest_name, Charset.forName("UTF-8")));
entity.addPart("code",
new StringBody(guest_code, Charset.forName("UTF-8")));
entity.addPart("picture", cbFile);
post.setEntity(entity);

HttpResponse response1 = client.execute(post);
HttpEntity resEntity = response1.getEntity();
String Response = EntityUtils.toString(resEntity);
Log.d("Response", Response);

} catch (IOException e) {
Log.e("asdf", e.getMessage(), e);

}
return null;

}

protected void onPostExecute(String file_url) {
// dismiss the dialog once product deleted
pDialog.dismiss();
if (file_url != null) {
Toast.makeText(MainScreen.this, file_url, Toast.LENGTH_LONG)
.show();
}

}
}

这就是 PHP。另请注意,我包括了我的数据库登录页面。您可以输入您的分贝。密码并在此处登录,但我选择不登录。

<?php
require("config.inc.php");
if (!empty($_POST)) {

if (empty($_POST['name'])) {
$response["success"] = 0;
$response["message"] = "Did not receive a name";
die(json_encode($response));
} else {
$name = $_POST['name'];
}


if (empty($_FILES['picture'])) {
$response["success"] = 0;
$response["message"] = "Did not receive a picture";
die(json_encode($response));
} else {
$file = $_FILES['picture'];
}


$target_path = "uploads/whatever-you-want-it-to-be/";
// It could be any string value above

/* Add the original filename to our target path.
Result is "uploads/filename.extension" */
$target_path = $target_path . basename( $_FILES['picture']['name']);

if(move_uploaded_file($_FILES['picture']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['picture']['name']).
" has been uploaded";
} else{
$response["success"] = 0;
$response["message"] = "Database Error. Couldn't upload file.";
die(json_encode($response));
}

} else {
$response["success"] = 0;
$response["message"] = "You have entered an incorrect code. Please try again.";
die(json_encode($response));
}

$query = "INSERT INTO name-of-table ( directory, name, photo ) VALUES ( directory, :name, :photo ) ";

$query_params = array(
':directory' => $directory,
':name' => $name,
':photo' => $_FILES['picture']['name']
);

try {
$stmt = $db->prepare($query);
$result = $stmt->execute($query_params);
}
catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error. Couldn't add path to picture";
die(json_encode($response));
}
$response["success"] = 1;
$response["message"] = "Picture Successfully Added!";
die (json_encode($response));


}

?>

关于php - 使用 JSON 从 Android 发送 Base64 图像到 php webservice,解码,保存到 SQL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18495663/

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