javascript - 你如何在 React 中换出一个组件？

Question

我正在尝试使用 React 构建单页应用程序。目前我有一个名为 App 的组件，它由 ReactDOM 呈现，它包含导航，然后是在导航组件之后呈现的组件(或页面)。

import React from 'react';
import Navigation from './Navigation';
import NavigationLink from './NavigationLink';
import Home from './Home';
import About from './About';

const App = () => (
  <div>
    <Navigation>
      <NavigationLink onClick={ ... }>Home</NavigationLink>
      <NavigationLink onClick={ ... }>About</NavigationLink>
    </Navigation>
    <Home />
  </div>
);

export default App;

我希望能够选择“关于”链接并将 Home 组件更新为 About。我正在寻找适用于两个以上元素(或页面)的解决方案。

这是我当前有效的代码，但这是一个非常糟糕的解决方案。

import React, { Component } from 'react';
import {
  NavItem,
  NavLink,
  UncontrolledDropdown,
  DropdownToggle,
  DropdownMenu,
  DropdownItem,
} from 'reactstrap';
import firebase from '../../utils/firebase';
import Navigation from '../../components/Navigation/Navigation';
import Login from '../Login/Login';
import Profile from '../Profile/Profile';
import Home from '../Home/Home';

class App extends Component {
  state = {
    currentShowingPage: 0,
    currentlyLoggedInUser: null,
    isLoginModalOpen: false,
  };

  componentDidMount = () => {
    firebase.auth().onAuthStateChanged((currentUser) => {
      if (currentUser) {
        this.setState({
          currentlyLoggedInUser: currentUser,
          isLoginModalOpen: false,
        });
      } else {
        this.setState({
          currentlyLoggedInUser: null,
        });
      }
    });
  };

  handleLoginModalToggle = () => {
    this.setState((previousState) => ({
      isLoginModalOpen: !previousState.isLoginModalOpen,
    }));
  };

  render = () => {
    let currentShowingPageComponent;

    const {
      isLoginModalOpen,
      currentlyLoggedInUser,
      currentShowingPage,
    } = this.state;

    if (currentShowingPage === 0) {
      currentShowingPageComponent = <Home />;
    } else if (currentShowingPage === 1) {
      currentShowingPageComponent = <Profile />;
    }

    return (
      <div>
        <Login
          isModalOpen={isLoginModalOpen}
          modalToggler={this.handleLoginModalToggle}
        />
        <Navigation>
          {currentlyLoggedInUser ? (
            <UncontrolledDropdown nav>
              <DropdownToggle nav caret>
                {currentlyLoggedInUser.email}
              </DropdownToggle>
              <DropdownMenu right>
                <DropdownItem
                  onClick={() =>
                    this.setState({
                      currentShowingPage: 1,
                    })
                  }
                >
                  Profile
                </DropdownItem>
                <DropdownItem disabled>Expeditions</DropdownItem>
                <DropdownItem divider />
                <DropdownItem onClick={() => firebase.auth().signOut()}>
                  Sign Out
                </DropdownItem>
              </DropdownMenu>
            </UncontrolledDropdown>
          ) : (
            <NavItem>
              <NavLink onClick={this.handleLoginModalToggle}>Login</NavLink>
            </NavItem>
          )}
        </Navigation>
        {currentShowingPageComponent}
      </div>
    );
  };
}

export default App;

Answer 1

这只是一个非常简单的切换组件的示例，有很多方法可以做到这一点，我相信您会得到更好的练习答案，但希望这能给您一些想法。 (如果不是很明显，您可以通过调用 setState({currentComponent: 'compX'})) 来使用它

getComponent(){
    let component;
    switch (this.state.currentComponent){
        case 'compA' :
            component = <CompA/>;
            break;
        case 'compB' :
            component = <CompB/>;
            break;
        case 'compC' :
            component = <CompC/>;
            break;
        case 'compD' :
            component = <CompD/>;
            break;
    }
    return component;
}

render(){
    return(
        <div>
            {this.getComponent()}
        </div>
    );
}