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android - DialogFragment 使用接口(interface)回调到 Target Fragment

转载 作者:塔克拉玛干 更新时间:2023-11-02 22:08:36 24 4
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我正在尝试将一些数据从 dialogfragment 发送到目标 fragment 但它不起作用。

我写了下面的代码,但是它通过了exception:

java.lang.NullPointerException: Attempt to invoke interface method 'void com.x.x.FragmentAlertDialog$Communicator.setI(java.lang.String)' on a null object reference

代码:

public class FragmentAlertDialog extends DialogFragment {

Communicator callback;

public interface Communicator {
void setI(String name);
}

public static FragmentAlertDialog newInstance(String id, int title, int items) {
FragmentAlertDialog frag = new FragmentAlertDialog();
Bundle args = new Bundle();
args.putString("id", id);
args.putInt("title", title);
args.putInt("items", items);
frag.setArguments(args);
return frag;
}

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
callback = (Communicator) getTargetFragment();
}

@Override
public Dialog onCreateDialog(Bundle savedInstanceState) {
String id = getArguments().getString("id");
int title = getArguments().getInt("title");
String[] items = getResources().getStringArray(getArguments().getInt("items"));
switch (id) {
case MainActivity.DIALOG_1:
return new AlertDialog.Builder(getActivity())
.setTitle(title)
.setItems(items, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
callback.setI("Important Data");
}
}).create();
}
return null;
}

fragment 类

public class FragmentXYXY extends Fragment implements View.OnClickListener, FragmentAlertDialog.Communicator {

@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.et_i:
DialogFragment newFragment = FragmentAlertDialog.newInstance(MainActivity.DIALOG_I, R.string.i_select, R.array.i_array);
newFragment.setTargetFragment(this, 0);
newFragment.show(getFragmentManager(), "dialog");
}
}

@Override
public void setI(String name) {
textI.setText(name);
}

谁能帮忙。谢谢

修改代码- newFragment.setTargetFragment(this, 0);

最佳答案

你必须调用setTargetFragment

setTargetFragment(this, 0);

为了在您的 DialogFragment 中获取引用 FragmentXYXY

@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.et_i:
DialogFragment newFragment = FragmentAlertDialog.newInstance(MainActivity.DIALOG_I, R.string.i_select, R.array.i_array);
newFragment.setTargetFragment(this, 0);
newFragment.show(getFragmentManager(), "dialog");
}
}

关于android - DialogFragment 使用接口(interface)回调到 Target Fragment,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30931674/

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