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php - JSON 请求发送空数据(swift)

转载 作者:塔克拉玛干 更新时间:2023-11-02 22:05:25 25 4
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我的 iOS 应用正在向网络服务发送空数据。我花了几个小时寻找解决方案,但没有任何效果。应用程序应该通过 php 脚本将一个 kontrah 号码发送到数据库。然后数据库必须识别是否可以在数据库中找到 kontrah 号码。如果号码正确,我会收到来自数据库服务器的请求。问题是我发送的号码肯定是正确的。我检查了发送到数据库的内容,它都是空的:

{"kontrah":null,"telefon":null,"opis":null,"afakt":null}

我已经制作了相同的应用程序,但在 Android Studio 中使用 Java 在 Android 上运行,一切正常。

我的代码:

@IBAction func submitAction(_ sender: AnyObject) {
let kontrah: String = fkontrah.text!
let telefon: String = ftelefon.text!



let json = [ "kontrah" : (kontrah), "telefon" : (telefon), "opis" : (selectedvalue), "afakt" : (selectedafakt) ]

print (json)

do {
let jsonData = try JSONSerialization.data(withJSONObject: json, options: .prettyPrinted)
print(jsonData)
// create post request
let url = NSURL(string: "http://hetman.pl/ios/post2.php")!
let request = NSMutableURLRequest(url: url as URL)
request.httpMethod = "POST"

// insert json data to the request
request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
request.httpBody = jsonData



let task = URLSession.shared.dataTask(with: request as URLRequest){ data, response, error in
if error != nil{
return
}

do {
let t = try JSONSerialization.jsonObject(with: data!, options: []) as? [String:AnyObject]
print(t)

} catch {
print("Error 43-> \(error)")
}
}
let alert = UIAlertController(title: "Wysłano poprawnie", message: "", preferredStyle: UIAlertControllerStyle.alert)
alert.addAction(UIAlertAction(title: "OK", style: UIAlertActionStyle.default, handler: nil))
self.present(alert, animated: true, completion: nil)


task.resume()


}

catch {
//handle error. Probably return or mark function as throws
print(error)
return
}
}
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
self.view.endEditing(true)
}

func textFieldShouldReturn(_ textField: UITextField) -> Bool {
textField.resignFirstResponder()
return(true)
}

}

日志:

2017-12-29 15:59:43.867463+0100 Hetman4[10692:4029622] Failed to set (titleLabel.adjustsFontSizeToFitWidth) user defined inspected property on (UITextView): [<UITextView 0x7fa1ad829e00> valueForUndefinedKey:]: this class is not key value coding-compliant for the key titleLabel.
2017-12-29 15:59:47.717492+0100 Hetman4[10692:4029622] [MC] System group container for systemgroup.com.apple.configurationprofiles path is /Users/bartoszlucinski/Library/Developer/CoreSimulator/Devices/3BE9103E-97CA-4E0B-AE53-6196EE08C49D/data/Containers/Shared/SystemGroup/systemgroup.com.apple.configurationprofiles
2017-12-29 15:59:47.717874+0100 Hetman4[10692:4029622] [MC] Reading from private effective user settings.
2017-12-29 15:59:52.225804+0100 Hetman4[10692:4029622] Can't find keyplane that supports type 4 for keyboard iPhone-PortraitChoco-NumberPad; using 4072550144015629828_PortraitChoco_iPhone-Simple-Pad_Default
["telefon": "510356448", "kontrah": "1400-685", "opis": "Świnia", "afakt": "0"]
94 bytes
2017-12-29 15:59:57.074868+0100 Hetman4[10692:4029622] Failed to set (titleLabel.adjustsFontSizeToFitWidth) user defined inspected property on (UITextView): [<UITextView 0x7fa1b0096400> valueForUndefinedKey:]: this class is not key value coding-compliant for the key titleLabel.
2017-12-29 15:59:57.628832+0100 Hetman4[10692:4029622] Presenting view controllers on detached view controllers is discouraged <Hetman4.ViewController: 0x7fa1ac428ef0>.
Optional(["error": <null>, "result": kontrah doesn't exist, "unAuthorizedRequest": 0, "success": 1])

PHP 脚本:

<?php
$kontrah = urlencode($_POST['kontrah']);
$telefon = urlencode($_POST['telefon']);
$opis = urlencode($_POST['opis']);
$afakt = urlencode($_POST['afakt']);

$url = 'https://hetman.e4b.com.pl/api/services/app/zlecenie/FormAddZlecenie?kontrah='.$kontrah.'&telefon='.$telefon.'&opis='.$opis.'&afakt='.&afakt;

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $fields_string);


$results = curl_exec($ch);

curl_close($ch);
?>

最佳答案

几个问题:

  1. 您的服务器需要 application/x-www-form-urlencoded 请求,而不是 JSON 请求。响应是 JSON,但请求不是。

  2. 当我使用 hetman.pl URL 时,它重定向到 www.hetman.pl,但将 POST 替换为获取。当我直接向 www.hetman.pl 发送请求时,我收到了不同的消息。不过,我无法阅读它们,所以我无法评论这是好是坏。

  3. 与手头的问题无关,可以稍微整理一下 Swift 代码,将 NSURLNSURLRequest 替换为 URLURLRequest

把它们放在一起,你会得到类似的东西:

let parameters = ["kontrah" : kontrah, "telefon" : telefon, "opis" : selectedvalue, "afakt" : selectedafakt]

let url = URL(string: "http://www.hetman.pl/ios/post2.php")!
var request = URLRequest(url: url)
request.httpMethod = "POST"
request.setValue("application/json", forHTTPHeaderField: "Accept")
request.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
request.setBodyContent(parameters)

let task = URLSession.shared.dataTask(with: request) { data, response, error in
guard let data = data, error == nil else {
print(error ?? "Unknown error")
return
}

do {
let t = try JSONSerialization.jsonObject(with: data) as? [String:AnyObject]
print(t ?? "Invalid")
} catch {
print("Error 43-> \(error)")
}
}
task.resume()

在哪里

extension URLRequest {

/// Populate the HTTPBody of `application/x-www-form-urlencoded` request
///
/// - parameter parameters: A dictionary of keys and values to be added to the request

mutating func setBodyContent(_ parameters: [String : String]) {
let parameterArray = parameters.map { (key, value) -> String in
let encodedKey = key.addingPercentEncoding(withAllowedCharacters: .urlQueryValueAllowed)!
let encodedValue = value.addingPercentEncoding(withAllowedCharacters: .urlQueryValueAllowed)!
return "\(encodedKey)=\(encodedValue)"
}
httpBody = parameterArray
.joined(separator: "&")
.data(using: .utf8)
}
}

extension CharacterSet {

/// Character set containing characters allowed in query value as outlined in RFC 3986.
///
/// RFC 3986 states that the following characters are "reserved" characters.
///
/// - General Delimiters: ":", "#", "[", "]", "@", "?", "/"
/// - Sub-Delimiters: "!", "$", "&", "'", "(", ")", "*", "+", ",", ";", "="
///
/// In RFC 3986 - Section 3.4, it states that the "?" and "/" characters should not be escaped to allow
/// query strings to include a URL. Therefore, all "reserved" characters with the exception of "?" and "/"
/// should be percent-escaped in the query string.
///
/// - parameter string: The string to be percent-escaped.
///
/// - returns: The percent-escaped string.

static var urlQueryValueAllowed: CharacterSet = {
let generalDelimitersToEncode = ":#[]@" // does not include "?" or "/" due to RFC 3986 - Section 3.4
let subDelimitersToEncode = "!$&'()*+,;="

var allowed = CharacterSet.urlQueryAllowed
allowed.remove(charactersIn: generalDelimitersToEncode + subDelimitersToEncode)

return allowed
}()

}

关于php - JSON 请求发送空数据(swift),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48025086/

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