android - 如何在android中的expandablelistview中获取组 View ？

Question

我是 blazilian 所以，我的英语不是很好。

所以..我需要在 expandablelistview 中获取组 View ，以便通过 view.getTag() 方法获取对象标签。

在这个例子中跟我学:

 ExpandableListView

    --> group (i need this view)
    ----> child
    ----> child
    ----> child

    --> group (i need this view)
    ----> child
    ----> child

我的代码:

    @Override
public boolean onChildClick(final ExpandableListView parent, final View v,
        final int groupPosition, final int childPosition, final long id) {

        /* I NEED GET VIEW OF GROUP FOR GET YOUR TAG*/

        View vParent = parent.getChildAt(groupPosition); // dont work after first group 
        Programa v2 = (Programa) parent.getTag(); // return null

        // v parameter is a child of group

    return true;
}

在我的适配器中:

    @Override
public View getGroupView(int groupPosition, boolean isExpanded,
        View convertView, ViewGroup parent) {

    TwoLineListItem view = (TwoLineListItem) LayoutInflater.from(contexto)
            .inflate(android.R.layout.simple_expandable_list_item_2,
                    parent, false);

    String programa = map.keySet().toArray(new String[map.keySet().size()])[groupPosition];

    view.getText1().setText(programa);
    view.getText2().setText("PROGRAMA LOCAL");

    view.setTag(programas.get(groupPosition)); // i need get this in child click listener

    return convertView = view;
}

有什么想法吗？谢谢

Answer 1

要从 ExpandableListView 获取组 View ，您可以执行以下操作:

public View getGroupView(ExpandableListView listView, int groupPosition) {
  long packedPosition = ExpandableListView.getPackedPositionForGroup(groupPosition);
  int flatPosition = listView.getFlatListPosition(packedPosition);
  int first = listView.getFirstVisiblePosition();
  return listView.getChildAt(flatPosition - first);
}