android - 使用 Baseadapter 过滤文本而不是图像过滤 ListView

Question

较早的问题有了一些进展。现在有一个新的问题。 GridView 中的文本显示正确的结果。但是，图像与列表开头的图像相同。

例如:如果我搜索“Sidd”，它会显示三个结果，但照片仍然以“A”开头的用户开头。为清楚起见，附上屏幕截图。

这是 BaseAdapter 代码:

public class TagFriendsAdapter extends BaseAdapter implements Filterable {

    List<String> arrayListNames;
    List<String> mOriginalNames;

    List<String> arrayPictures;
    List<String> mOriginalPictures;

    Activity activity;
    String[] fetFriendID;
    String[] fetFriendName;
    String[] fetFriendPicture;

    LayoutInflater inflater = null;
    ImageLoader imageLoader;

    TagFriendsAdapter(Activity a, String[] stringUID, String[] stringName, String[] stringPicture,
            ArrayList<String> arrayName, ArrayList<String> arrayPicture) {

        activity = a;
        fetFriendID = stringUID;
        fetFriendName = stringName;
        fetFriendPicture = stringPicture;

        this.arrayListNames = arrayName;
        this.arrayPictures = arrayPicture;

        inflater = (LayoutInflater)activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        imageLoader = new ImageLoader(activity.getApplicationContext());
    }

    public int getCount() {
        return arrayListNames.size();
    }

    public Object getItem(int position) {
        return position;
    }

    public long getItemId(int position) {
        return position;
    }

    @Override
    public void notifyDataSetChanged() {
        super.notifyDataSetChanged();
    }

    public View getView(final int position, View convertView, ViewGroup parent) {
        View vi = convertView;
        if(convertView == null)
            vi = inflater.inflate(R.layout.friends_grid_items, null);

        ImageView imgProfilePicture = (ImageView)vi.findViewById(R.id.imgProfilePicture);
        TextView txtUserName = (TextView)vi.findViewById(R.id.txtUserName);

        txtUserName.setText(arrayListNames.get(position));

        if (arrayPictures.get(position) != null){
            imageLoader.DisplayImage(arrayPictures.get(position), imgProfilePicture);
        }
        else if (arrayPictures.get(position) == null) {
            imgProfilePicture.setVisibility(View.GONE);
        }

        return vi;
    }

    @Override
    public Filter getFilter() {

        Filter filter = new Filter() {

            @SuppressWarnings("unchecked")
            @Override
            protected void publishResults(CharSequence constraint, FilterResults results) {

                arrayListNames = (List<String>) results.values;
                notifyDataSetChanged();
            }

            @Override
            protected FilterResults performFiltering(CharSequence constraint) {

                FilterResults results = new FilterResults();
                ArrayList<String> FilteredArrayNames = new ArrayList<String>();

                if (mOriginalNames == null && mOriginalPictures == null)    {
                    mOriginalNames = new ArrayList<String>(arrayListNames);
                    mOriginalPictures = new ArrayList<String>(arrayPictures);
                }
                if (constraint == null || constraint.length() == 0) {
                    results.count = mOriginalNames.size();
                    results.values = mOriginalNames;
                } else {
                    constraint = constraint.toString().toLowerCase();
                    for (int i = 0; i < mOriginalNames.size(); i++) {
                        String dataNames = mOriginalNames.get(i);
                        if (dataNames.toLowerCase().startsWith(constraint.toString()))  {
                            FilteredArrayNames.add(dataNames);
                        }
                    }

                    results.count = FilteredArrayNames.size();
                    System.out.println(results.count);

                    results.values = FilteredArrayNames;
                    Log.e("VALUES", results.values.toString());
                }

                return results;
            }
        };

        return filter;
    }

}

和截图:

Answer 1

首先重构您的代码。创建一个将姓名、照片和其他 friend 数据保存在一起的类。

class Friend {
    public String name;
    public String picture;
    ... /* more members and access methods*/
};

然后相应地修改您的适配器和过滤代码。

• FilterResults应包含 ArrayList<Friend> ，即 Friend 的列表对象而不仅仅是名称。

• 在适配器中，替换

  List<String> arrayListNames;
List<String> arrayPictures;

  与

  List<Friend> friendsList;

• 更改 getView从 friendsList 访问数据的方法对象列表。

经过这些更改后，代码看起来会更好，工作也会更好。

更新:

确保您的适配器的 getItem方法返回 Friend对象

public Object getItem(int position) {
    return mFriendsList.get(position);
}