ios - 无法为 armv6 构建 RestKit

Question

我经常收到这样的警告:

warning: no rule to process file '$(PROJECT_DIR)/Vendor/YAJL/NSBundle+YAJL.m' of type sourcecode.c.objc for architecture armv6 
warning: no rule to process file '$(PROJECT_DIR)/Vendor/YAJL/NSObject+YAJL.m' of type sourcecode.c.objc for architecture armv6 
warning: no rule to process file '$(PROJECT_DIR)/Vendor/YAJL/yajl-1.0.9/src/yajl.c' of type sourcecode.c.c for architecture armv6 
warning: no rule to process file '$(PROJECT_DIR)/Vendor/YAJL/yajl-1.0.9/src/yajl_alloc.c' of type sourcecode.c.c for architecture armv6
....

尝试在 Architectures 构建选项中使用“armv6”标志编译 RestKit。由于编译器找不到编译文件的规则，它根本不编译它们，所以我无法在设备上安装应用程序，因为它说找不到已编译的库。我尝试了在互联网上找到的不同方法，但它们仍然不起作用。谁能解释这个问题的核心及其发生的原因？

Answer 1

您运行的是 Xcode 4.5 吗？ 4.5 版本已经放弃了对 armv6 的支持