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javascript - 如果值不更改,如何跳过 'if' 语句 Hangman Javascript

转载 作者:塔克拉玛干 更新时间:2023-11-02 21:41:11 26 4
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我正在做一个编码练习,使用 jQuery/Javascript 制作刽子手游戏。我的游戏的大部分功能都有效:获取新词、更新猜测等。但是问题出在 函数 reviewLives() 中,涉及 if 语句和调用的绘制函数。这是代码:

//Draw functions
function drawHead() {
$('.draw-area').append($('<div>').addClass("body-part head"));
}
function drawTorso() {
$('.draw-area').append(
$('<div>').addClass("body-part armbox").append(
$('<div>').addClass("body-part torso")));
$('.draw-area').append(
$('<div>').addClass("body-part legbox").append(
$('<div>').addClass("body-part pelvis")));
}
function drawLeftArm(){
$('.armbox').prepend($('<div>').addClass('body-part leftarm'));
}
function drawRightArm(){
$('.armbox').prepend($('<div>').addClass('body-part rightarm'));
}
function drawLeftLeg(){
$('.legbox').prepend($('<div>').addClass('body-part leftleg'));
}
function drawRightLeg(){
$('.legbox').prepend($('<div>').addClass('body-part rightleg'));
}
var drawSequence = [drawHead,drawTorso,drawLeftArm,drawRightArm,drawLeftLeg,drawRightLeg];



//

var wordlist = ['tree', 'mail', 'male', 'female'];

var guesses = [];
var targetWord = '';
var maxLives = 7;

function newWord() {
targetWord = wordlist[Math.floor(Math.random() * wordlist.length)];
return targetWord;
}
console.log('Your word is: ' + newWord());
//go through string of answer word and guesses
function obfuscateWord(){
// temp variable
var obWord = '';
// loop through target word as an array and loop through with the guesses made
for (var i=0; i<targetWord.length; i++) {
//target letter word is not being guessed
if (guesses.indexOf(targetWord[i].toLowerCase(), 0) == -1) {
obWord += '_ ';
} else {
obWord += targetWord[i];
}

}
return obWord;
}


//function to draw the spaces on the screen
function drawWord() {
while (targetWord == '') {
newWord();
}
//specify the div with targetWOrd ID
$('#targetWord').html(obfuscateWord());
}

//for guessed Letters
function drawGuesses() {
guesses.sort();
$('#previousGuesses').html(guesses.join(', '));
//console.log('this is guesses0: '+guesses)
}

//remove duplicates
function cleanGuess() {
//temporary variable
var uniqueGuesses = [];
//for each guess perform function
$.each(guesses, function(index, element) {
//if guess is not in unique guesses push it, otherwise skip it
//if element is not empty, test if it is in array
if (element.length > 0 && $.inArray(element, uniqueGuesses) == -1) {
uniqueGuesses.push(element);

} else {
alert('You already guessed this letter!');
}

});
//override current guesses with uniqueGuesses
guesses = uniqueGuesses;
}





//to populate the array with guesses, when a letter is input by user
function addGuess() {
//filter out to only have a alphabet using a type test

if(/^[a-zA-Z]*$/.test($('#guess').val()) && typeof $('#guess').val() !== "undefined") {
//if passes test push into the array
guesses.push($('#guess').val().toLowerCase());
}
//to 'empty' the user input
$('#guess').val('');
}




// use for win or lose, isWinner true or false
function endGameDialog(isWinner) {
if (isWinner) {
//alert
//set html of #endGame dialog b ox
$('#endGameDialogTitle').html('You won');
$('#endGameDialogContent').html('You guessed '+targetWord+' in '+guesses.length+' attempts!');

} else {

//alert
//set html of #endGame dialog b ox
$('#endGameDialogTitle').html('You Lost');
$('#endGameDialogContent').html('The word was '+targetWord+'');

}

//$('#endGameDialog'.modal('toggle'))
}


console.log('this is guesses: '+guesses)
function reviewLives() {
var livesRemaining = maxLives,
string = targetWord.toLowerCase();
console.log('this is string:' + string)
for (var i = 0; i < guesses.length; i++) {
if (string.indexOf(guesses[i], 0) == -1) {
livesRemaining--;
//console.log(guesses[i])
}
}

if (livesRemaining === 6) {
drawSequence[0]();
} else if (livesRemaining===5) {
drawSequence[1]();
} else if (livesRemaining===4) {
drawSequence[2]();
} else if (livesRemaining===3) {
drawSequence[3]();
} else if (livesRemaining===2) {
drawSequence[4]();
} else if (livesRemaining===1) {
drawSequence[5]();
endGameDialog(false);
}

console.log('livesRemaining is: '+livesRemaining);


}

function checkIfWon() {
if (obfuscateWord() == targetWord) {
endGameDialog(true);
}
}

function resetGame() {
//setImage(0);
targetWord = '';
guesses = [];
newWord();
console.log(newWord())
}

//when key is pressed call the following functions
function update() {
addGuess();
cleanGuess();
drawWord();
drawGuesses();
reviewLives();
checkIfWon();
}


$(document).ready(function() {
//loadWordlist();
drawWord();
drawGuesses();
$('#guess').attr('onkeyup', 'update();');
});
body { 
font-family:sans-serif;
font-weight:bold;
font-size:16pt;
}
/* Topmatter */
.topmatter {
height:210px;
}
.bottommatter{
background:#f1f1f1;
height:auto;
}
/* For the left 'Guess A Letter!' and 'Guessed Letter' boxes. */
.side-container {
margin-top:45px;
margin-left:130px;
width:170px;
text-align:center;
}
.container-title {
color:#6f5a2d;
}
.input-area {
width:75px;
height:31px;
margin:auto;
padding:3pt;
border: 1px #6f5a2d solid;
-moz-border-radius:15px;
-webkit-border-radius:15px;
border-radius:15px;
background:#ebe2ce;
}
#letter-input {
border:1px #6f5a2d solid;
width:20pt;
font-size:14pt;
text-align:center;
}
.guessed-letter {
color:#792c15;
}
/* Word Box */
.word-box {
width:250px;
margin:auto;
margin-top:25px;
text-align:center;
}
.word-display {
background:#ebe2ce;
border:1px #6f5a2d solid;
height:31px;
padding:3pt;
-moz-border-radius:15px;
-webkit-border-radius:15px;
border-radius:15px;
}
.shown-letter {
border-bottom: 3px #000 solid;
padding: 0 2px;
margin: 0 2px;
color:#1c2025;
}
/* Hangman Area */
.hang-container {
margin-top:-10px;
margin-right: 90px;
width:200px;
height:205px;
float:right;
}
.scaffolding-top {
width:108px;
height:5px;
background:#332915;
}
.scaffolding-left {
width:5px;
height:200px;
background:#332915;
float:left;
}
.scaffolding-base {
width:150px;
height:5px;
background:#332915;
}
.draw-area {
width:200px;
height:200px;
text-align:center;
}
.rope {
margin:auto;
height:25px;
width:5px;
background:#a59885;
}
.head {
margin:auto;
height:30px;
width:30px;
background:#000;
-webkit-border-radius: 15px;
-moz-border-radius:15px;
border-radius:15px;
}
.armbox {
margin:auto;
width:100px;
}
.leftarm {
float:left;
height:10px;
width:45px;
background:#000;
}
.rightarm {
float:right;
height:10px;
width:45px;
background:#000;
}
.torso {
margin:auto;
width:10px;
height:50px;
background:#000;
}
.legbox {
margin:auto;
height:60px;
width:30px;
}
.leftleg {
float:left;
width:10px;
height:60px;
background:#000;
}
.rightleg {
float:right;
width:10px;
height:60px;
background:#000;
}
.pelvis {
margin:auto;
height:10px;
width:10px;
background:#000;
}
<html>
<head>
<title>Hangman Game</title>
<link rel="stylesheet" type="text/css" href="page.css">
</head>
<body>
<div class='topmatter'>
<div class='hang-container'>
<div class='scaffolding-top'></div>
<div class='scaffolding-left'></div>

<div class='draw-area'>
<div class='rope'></div>
</div>

<div class='scaffolding-base'></div>
</div>
<div class='side-container'>
<div class='container-title'>Guess A Letter!</div>
<div class='input-area'>
<input id='guess' type='text' maxlength='1'/>
</div>
</div>

<div class='side-container'>
<div class='container-title'>Guessed Letters</div>
<div id="previousGuesses" class='input-area'></div>
</div>
</div>
<div class='bottommatter'>
<div class='word-box'>
<div class='word-display' id='targetWord'>
</div>
</div>
</div>
<div id='endGameDialogTitle'>
Win or Lose
</div>


</body>
<script src='ui.js'></script>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
</head>
</html>

再次输入错误的字母时,问题就开始了。虽然第一次输入错误的字母确实会绘制火柴人的一部分,但如果用户再次输入相同错误的字母,则会弹出警报以通知 key 已经被按下,它绘制火柴人的相同部分(即它会绘制第二个头)。我知道这是因为 livesRemaining 的值没有被更新,这导致它再次绘制相应的“drawFoobar”。我可以使用什么样的逻辑/语句来防止任何额外的绘制尝试?

这是我困扰的具体功能:`

function reviewLives() {
var livesRemaining = maxLives,
string = targetWord.toLowerCase();
console.log('this is string:' + string)
for (var i = 0; i < guesses.length; i++) {
if (string.indexOf(guesses[i], 0) == -1) {
livesRemaining--;
//console.log(guesses[i])
}
}

if (livesRemaining === 6) {
drawSequence[0]();
} else if (livesRemaining===5) {
drawSequence[1]();
} else if (livesRemaining===4) {
drawSequence[2]();
} else if (livesRemaining===3) {
drawSequence[3]();
} else if (livesRemaining===2) {
drawSequence[4]();
} else if (livesRemaining===1) {
drawSequence[5]();
endGameDialog(false);
}

console.log('livesRemaining is: '+livesRemaining);


}

`

最佳答案

例如你可以添加一个全局变量

var letterGuessed = false;

并且在 cleanGuess 函数中,当您提醒文本“您已经猜到了这封信!”时将变量 letterGuessed 设置为 true

alert('You already guessed this letter!');
letterGuessed = true;//add

然后在 reviewLives 函数中首先检查变量 letterGuessed 是否等于 false,然后在退出 for 循环后将变量 letterGuessed 设置回 false像这样

function reviewLives() {
var livesRemaining = maxLives,
string = targetWord.toLowerCase();
console.log('this is string:' + string)
for (var i = 0; i < guesses.length; i++) {
if (!letterGuessed && string.indexOf(guesses[i], 0) == -1) {//==========add !letterGuessed &&
livesRemaining--;
//console.log(guesses[i])
}
}
letterGuessed = false;//==========add

if (livesRemaining === 6) {
drawSequence[0]();
} else if (livesRemaining===5) {
drawSequence[1]();
} else if (livesRemaining===4) {
drawSequence[2]();
} else if (livesRemaining===3) {
drawSequence[3]();
} else if (livesRemaining===2) {
drawSequence[4]();
} else if (livesRemaining===1) {
drawSequence[5]();
endGameDialog(false);
}

console.log('livesRemaining is: '+livesRemaining);

}

关于javascript - 如果值不更改,如何跳过 'if' 语句 Hangman Javascript,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38887071/

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