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ios - 从另一个 NSDictionary 中提取一个 NSDictionary

转载 作者:塔克拉玛干 更新时间:2023-11-02 21:36:41 30 4
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我的应用程序有一个 NSDictionary,其中包含许多其他 NSDictionary。如果我打印出这本词典,它的内容如下:

oxip =     {
created = "2014-02-10 14:42:59";
lastMsgId = "";
requestTime = "1.6434";
response = {
code = 001;
debug = "";
message = success;
request = getHierarchyByMarketType;
text = "\n";
williamhill = {
class = {
id = 1;
maxRepDate = "2014-02-10";
maxRepTime = "07:31:48";
name = "UK Football";
text = "\n";
type = (
{
id = 2;
lastUpdateDate = "2013-12-26";
lastUpdateTime = "13:32:54";
market = (
{
betTillDate = "2014-02-15";
betTillTime = "15:00:00";
date = "2014-02-15";
id = 140780553;
lastUpdateDate = "2014-02-10";
lastUpdateTime = "14:09:13";
name = "Queen of the South v Dundee - Match Betting";
participant = (
{
handicap = "";
id = 496658381;
lastUpdateDate = "2014-02-10";
lastUpdateTime = "14:09:13";
name = Dundee;
odds = "11/8";
oddsDecimal = "2.38";
text = "\n\n\n\n\n\n";
},
{
handicap = "";
id = 496658380;
lastUpdateDate = "2014-02-10";
lastUpdateTime = "14:09:13";
name = Draw;
odds = "5/2";
oddsDecimal = "3.50";
text = "\n";
},
{
handicap = "";
id = 496658379;
lastUpdateDate = "2014-02-10";
lastUpdateTime = "14:09:13";
name = "Queen of the South";
odds = "11/8";
oddsDecimal = "2.38";
text = "\n";
}
);
text = "\n";
time = "15:00:00";
}

我的应用程序到达名称为 NSDictionary 的最佳方式是什么:

name = "Queen of the South v Dundee - Match Betting"

不需要遍历每个单独的字典并找到它的键对象?

最佳答案

您可以为此使用 valueForKeyPath。它接受一条由点分隔的路径。示例:

NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:@"https://dl.dropboxusercontent.com/u/1365846/21680479.json"]]
options:0
error:nil];
NSLog(@"%@", [dict valueForKeyPath:@"response.williamhill.class.type.market.name"]);

这取决于字典的表示。如果 williamhill 部分发生变化,那么它当然不起作用。

关于ios - 从另一个 NSDictionary 中提取一个 NSDictionary,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21680479/

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