javascript - 在 Javascript 中匹配两个多维数组

Question

我有两个多维数组，我想创建第三个多维数组:

var reports = [
    [48.98,153.48],
    [12.3,-61.64]
    ];

var vulc = [
    ["ciccio",48.98,153.48],
    ["cicci",12.3,-61.64],
    ["intruso",59.9,99.9]
    ];

我想创建一个新的多维数组

var nuovarray= [];  


for (i=0; i<= reports.length; i++) {

   var attivi= reports[i];
   var attlat= attivi[0];
   var attlng= attivi[1];

    for (s=0;  s<=vulc.length; s++){
     var vulca= vulc[s];
     var vulcanam= vulca[0];
     var vulcalat= vulca[1];
     var vulcalng= vulca[2];

        if ((vulcalat==attlat) && (vulcalng==attlng){
            var stato= "A";
            nuovarray.push([vulcanam,vulcalat,vulcalng,stato]);     
        } 
        else{
            var stato= "N";
            nuovaarray.push([vulcanam,vulcalat,vulcalng,stato]);     
        }    

    }

}

我想拥有

var nuovarray= [
    ["ciccio",48.98,153.48,"N"],
    ["cicci",12.3,-61.64,"N"],
    ["intruso",59.9,99.9,"A"]
    ];

但是我不知道这段代码好不好:/

Answer 1

正如我在评论中所说，在 for 循环中，使用 < not <= (array of length N has indexes 0 ... N-1) ... 并将外循环与内循环交换，并且仅如果内循环没有用值“A”推送，则在外循环结束前用值“N”推送

var reports = [
    [48.98,153.48],
    [12.3,-61.64]
];

var vulc = [
    ["ciccio",48.98,153.48],
    ["cicci",12.3,-61.64],
    ["intruso",59.9,99.9]
];

var nuovarray= [];  

for(var s = 0; s < vulc.length; s++) {
    var vulca = vulc[s];
    var stato= "A"; // default, no match
    var vulcanam= vulca[0];
    var vulcalat= vulca[1];
    var vulcalng= vulca[2];

    for(var i = 0; i < reports.length; i++) {
        var attivi = reports[i];
        var attlat= attivi[0];
        var attlng= attivi[1];
    
        if ((vulcalat==attlat) && (vulcalng==attlng)) {
            stato = "N";
            break; // we've found a match, so set stato = N and stop looping
        }
    }
    nuovarray.push([vulcanam,vulcalat,vulcalng,stato]);     
}


document.getElementById('result').innerHTML = (nuovarray).toSource();

<div id='result'></div>