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javascript - 如果填充了任何相关对象字段,如何使 ng-required 为真?

转载 作者:塔克拉玛干 更新时间:2023-11-02 21:28:28 25 4
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默认情况下,第一个人的详细信息 required="true" 但其他人的表格 required="true" 取决于其是否填写。

代码片段当前的问题是,当最后一个人的任何一个字段被填充时,它是无效的。

演示:http://plnkr.co/edit/WUpybR1tNq5QFjlTB2E7?p=preview

var app = angular.module('plunker', []);
app.controller('MainCtrl', function($scope) {
$scope.person = [{isRequired: true}, {isRequired: false}, {isRequired: false}, {isRequired: false}];
$scope.members = {};
$scope.submitForm = function() {
console.clear();
if (typeof $scope.members != 'undefined' && Object.keys($scope.members).length) {
var numMembers = Object.keys($scope.members).length;
for (i = 0; i < numMembers; i++) {
if (Object.keys($scope.members[i]).length <= 2) {
$scope.person[i].isRequired = true;
}
}
} else {
$scope.person = [{isRequired: true}, {isRequired: false}, {isRequired: false}, {isRequired: false}];
}
}
});
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://code.angularjs.org/1.4.8/angular.js" data-semver="1.4.9"></script>
<div ng-app="plunker" ng-controller="MainCtrl" class="container">
<form name="myForm" ng-submit="submitForm(myForm.$valid)" novalidate>
<h4>First person</h4>
<div class="form-group" ng-class="{ 'has-error' : (myForm.$submitted && myForm.firstnameOne.$invalid) || (!myForm.firstnameOne.$pristine && myForm.firstnameOne.$invalid)}">
<label>First Name</label>
<input type="text" class="form-control" name="firstnameOne" placeholder="First Name" ng-model="members[0].fname" ng-required="person[0].isRequired">
</div>
<div class="form-group" ng-class="{ 'has-error' : (myForm.$submitted && myForm.lastnameOne.$invalid) || (!myForm.lastnameOne.$pristine && myForm.lastnameOne.$invalid)}">
<label>Last Name</label>
<input type="text" class="form-control" name="lastnameOne" placeholder="Last Name" ng-model="members[0].lname" ng-required="person[0].isRequired">
</div>
<h4>Second person</h4>
<div class="form-group" ng-class="{ 'has-error' : (myForm.$submitted && myForm.firstnameSecond.$invalid) || (!myForm.firstnameSecond.$pristine && myForm.firstnameSecond.$invalid)}">
<label>First Name</label>
<input type="text" class="form-control" name="firstnameSecond" placeholder="First Name" ng-model="members[1].fname" ng-required="person[1].isRequired">
</div>
<div class="form-group" ng-class="{ 'has-error' : (myForm.$submitted && myForm.lastnameSecond.$invalid) || (!myForm.lastnameSecond.$pristine && myForm.lastnameSecond.$invalid)}">
<label>Last Name</label>
<input type="text" class="form-control" name="lastnameSecond" placeholder="Last Name" ng-model="members[1].lname" ng-required="person[1].isRequired">
</div>
<h4>Last person</h4>
<div class="form-group" ng-class="{ 'has-error' : (myForm.$submitted && myForm.firstnameThird.$invalid) || (!myForm.firstnameThird.$pristine && myForm.firstnameThird.$invalid)}">
<label>First Name</label>
<input type="text" class="form-control" name="firstnameThird" placeholder="First Name" ng-model="members[2].fname" ng-required="person[2].isRequired">
</div>
<div class="form-group" ng-class="{ 'has-error' : (myForm.$submitted && myForm.lastnameThird.$invalid) || (!myForm.lastnameThird.$pristine && myForm.lastnameThird.$invalid)}">
<label>Last Name</label>
<input type="text" class="form-control" name="lastnameThird" placeholder="Last Name" ng-model="members[2].lname" ng-required="person[2].isRequired">
</div>
<button type="submit" class="btn btn-primary">Submit</button>
</form>
<br><hr>
<h4>Data</h4>
<pre>{{members | json}}</pre>
<h4>Validation</h4>
<pre>{{person | json}}</pre>
</div>

最佳答案

您几乎是对的 - 您的代码存在一个小问题。

var numMembers = Object.keys($scope.members).length; // <-- length of keys
for (i = 0; i < numMembers; i++) { // <-- iterate over length, not actual indexes
if (Object.keys($scope.members[i]).length <= 2) {
$scope.person[i].isRequired = true;
}
}

在您的代码中,您将 i 计算为根据 $scope.members 的键创建的数组的索引。假设您填写了 FirstLast 表单,获得 $scope.members = {0: ..., 2: ...}键。

现在,当您调用此行 var numMembers = Object.keys($scope.members).length; 时,您会得到 numMembers = 2,并且在您的for 循环你评估你的 if 条件,对于你的第二个 i,你得到这个:Object.keys($scope.members[ 1]).length,但是您的成员变量中没有 1 键,因此出现错误。

要解决此问题,请将 for 循环基于现有键数组本身:

var members = Object.keys($scope.members);
for (i = 0; i < members.length; i++) {
if (Object.keys($scope.members[members[i]]).length <= 2) { // Check key length of the existing keys only.
$scope.person[members[i]].isRequired = true;
}
}

Here是你的 plunker 的工作叉。

关于javascript - 如果填充了任何相关对象字段,如何使 ng-required 为真?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37271832/

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