java - Android 地理编码功能不如 iOS

Question

所以我有一个将地址(字符串)转换为坐标的函数。

这是它在 iOS 中的样子:

func setCoords(buildet: BuildingDetail) {

    let geoCoder = CLGeocoder()

    geoCoder.geocodeAddressString(buildet.address, completionHandler:
        {(placemarks: [AnyObject]!, error: NSError!) in

            if error != nil {
                println("Geocode failed with error: \(error.localizedDescription)")
            } else if placemarks.count > 0 {
                let placemark = placemarks[0] as! CLPlacemark
                let location = placemark.location
                buildet.lat = location.coordinate.latitude
                buildet.lon = location.coordinate.longitude
            }
            self.setupMarker(buildet)
    })
}

这是它在 Android 中的样子:

public static double[] getLatLongPositions(String address) throws Exception
{
    int responseCode = 0;
    String api = "http://maps.googleapis.com/maps/api/geocode/xml?address=" + URLEncoder.encode(address, "UTF-8") + "&sensor=true";
    System.out.println("URL : "+api);
    URL url = new URL(api);
    HttpURLConnection httpConnection = (HttpURLConnection)url.openConnection();
    httpConnection.connect();
    responseCode = httpConnection.getResponseCode();
    if(responseCode == 200)
    {
        DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();;
        Document document = builder.parse(httpConnection.getInputStream());
        XPathFactory xPathfactory = XPathFactory.newInstance();
        XPath xpath = xPathfactory.newXPath();
        XPathExpression expr = xpath.compile("/GeocodeResponse/status");
        String status = (String)expr.evaluate(document, XPathConstants.STRING);
        if(status.equals("OK"))
        {
            expr = xpath.compile("//geometry/location/lat");
            String latitude = (String)expr.evaluate(document, XPathConstants.STRING);
            expr = xpath.compile("//geometry/location/lng");
            String longitude = (String)expr.evaluate(document, XPathConstants.STRING);
            return new double[] {Double.parseDouble(latitude), Double.parseDouble(longitude)};
        }
    }
    return new double[]{0,0};
}

现在，上面的 iOS 函数只运行 setupMarker 函数，Android 方法返回坐标，没什么大不了的!

我遇到的问题是，我为两个函数提供了完全相同的地址参数。

iOS 完美返回所有坐标。

而 Android 只能正确返回其中的大约 30%。

是否有与上述 iOS 等效的 Android 功能，或者只有一个可以正确地理编码的功能。

如您所见，Android 会在此处调用 API:

http://maps.googleapis.com/maps/api/geocode/xml?address=

而且我已经测试过了，它并没有给出很好的结果，至少不如 iOS。

我该怎么办？

编辑 - 一些示例(所有适用于 iOS)

• EBS，2 伯灵顿路，都柏林 2
• AIB Bankcentre, Merrion Road, Ballsbridge, Dublin 4, Ireland
• AIB，Unit 33, Sandyford Business Centre, Sandyford, Dublin 18

Answer 1

尝试使用返回 JSON 格式数据的 URL，然后您可以解析并获取纬度和经度。这是一个例子:

public static void getLatLongFromAddress(String youraddress) {
String uri = "http://maps.google.com/maps/api/geocode/json?address=" +
              youraddress + "&sensor=false";
HttpGet httpGet = new HttpGet(uri);
HttpClient client = new DefaultHttpClient();
HttpResponse response;
StringBuilder stringBuilder = new StringBuilder();

try {
    response = client.execute(httpGet);
    HttpEntity entity = response.getEntity();
    InputStream stream = entity.getContent();
    int b;
    while ((b = stream.read()) != -1) {
        stringBuilder.append((char) b);
    }
} catch (ClientProtocolException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}

JSONObject jsonObject = new JSONObject();
try {
    jsonObject = new JSONObject(stringBuilder.toString());

    double lng = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
        .getJSONObject("geometry").getJSONObject("location")
        .getDouble("lng");

    double lat = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
        .getJSONObject("geometry").getJSONObject("location")
        .getDouble("lat");

    Log.d("latitude", "" + lat);
    Log.d("longitude", "" + lng);
} catch (JSONException e) {
    e.printStackTrace();
}

} 

希望这对您有所帮助。