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我需要重新组织我的 json 数据,使其基于当前嵌套在数据中两层以下的键。数据带有基于事件的“id”、“name”等的层次结构。我需要将层次结构基于“年”,它位于每个项目的“年”数组中。我尝试了各种方法,但我什至不确定我是否应该使用 d3.nest 或 d3.map(或两者)。
我没有费心发布我的 d3 代码,因为我在这个阶段所做的就是加载数据并将其记录到控制台。
非常感谢任何帮助。
传入的数据:
[{
"id": 2,
"name": "Test activity 51",
"code": "D51",
"description": "Description goes here.",
"years": [{
"id": 8,
"year": "2020-2021",
"target": 65,
"weeks": [{
"week_ending": "2020-12-06",
"hours": 4.0
}, {
"week_ending": "2020-12-06",
"hours": 2.5
}, {
"week_ending": "2020-10-18",
"hours": 2.0
}, {
"week_ending": "2020-07-19",
"hours": 2.0
}]
}, {
"id": 11,
"year": "2019-2020",
"target": 40,
"weeks": [{
"week_ending": "2020-01-05",
"hours": 3.0
}, {
"week_ending": "2019-09-15",
"hours": 5.5
}, {
"week_ending": "2019-07-14",
"hours": 1.5
}]
}, {
"id": 10,
"year": "2018-2019",
"target": 40,
"weeks": [{
"week_ending": "2018-09-30",
"hours": 3.0
}]
}]
}, {
"id": 3,
"name": "Test activity 63",
"code": "D63",
"description": null,
"years": [{
"id": 2,
"year": "2019-2020",
"target": 15,
"weeks": [{
"week_ending": "2020-05-24",
"hours": 2.0
}, {
"week_ending": "2020-03-22",
"hours": 4.0
}, {
"week_ending": "2020-01-26",
"hours": 5.0
}, {
"week_ending": "2020-01-19",
"hours": 4.0
}, {
"week_ending": "2019-12-01",
"hours": 4.5
}, {
"week_ending": "2019-08-25",
"hours": 2.0
}, {
"week_ending": "2019-07-21",
"hours": 3.0
}]
}, {
"id": 9,
"year": "2018-2019",
"target": 30,
"weeks": [{
"week_ending": "2018-08-19",
"hours": 3.5
}, {
"week_ending": "2019-02-10",
"hours": 5.0
}, {
"week_ending": "2018-12-30",
"hours": 3.0
}, {
"week_ending": "2018-10-21",
"hours": 2.0
}, {
"week_ending": "2018-08-26",
"hours": 4.0
}]
}]
}, {
"id": 1,
"name": "Test activity 27",
"code": "D27",
"description": "Description goes here.",
"years": [{
"id": 4,
"year": "2019-2020",
"target": 30,
"weeks": [{
"week_ending": "2020-04-05",
"hours": 2.0
}, {
"week_ending": "2020-03-22",
"hours": 6.0
}, {
"week_ending": "2020-01-12",
"hours": 1.0
}]
}, {
"id": 1,
"year": "2018-2019",
"target": 25,
"weeks": [{
"week_ending": "2018-11-18",
"hours": 6.0
}, {
"week_ending": "2018-10-21",
"hours": 2.0
}, {
"week_ending": "2018-10-07",
"hours": 6.0
}]
}]
}, {
"id": 10,
"name": "Test activity 59",
"code": "D59",
"description": null,
"years": [{
"id": 13,
"year": "2020-2021",
"target": 15,
"weeks": [{
"week_ending": "2021-04-18",
"hours": 4.0
}, {
"week_ending": "2021-02-28",
"hours": 2.0
}, {
"week_ending": "2021-02-14",
"hours": 5.0
}, {
"week_ending": "2020-11-22",
"hours": 3.0
}, {
"week_ending": "2020-08-16",
"hours": 2.0
}]
}, {
"id": 14,
"year": "2019-2020",
"target": 18,
"weeks": [{
"week_ending": "2019-12-01",
"hours": 2.0
}, {
"week_ending": "2019-10-27",
"hours": 9.0
}, {
"week_ending": "2019-09-01",
"hours": 2.5
}]
}, {
"id": 12,
"year": "2018-2019",
"target": 20,
"weeks": [{
"week_ending": "2018-11-11",
"hours": 4.0
}, {
"week_ending": "2018-08-26",
"hours": 1.0
}, {
"week_ending": "2018-08-12",
"hours": 12.0
}]
}]
}]
我要实现的目标:
[{
"year": "2020-2021",
"values": [{
"name": "Test activity 51",
"code": "D51",
"description": "Description goes here.",
"target": 65,
"weeks": [{
"week_ending": "2020-12-06",
"hours": 4.0
}, {
"week_ending": "2020-12-06",
"hours": 2.5
}, {
"week_ending": "2020-10-18",
"hours": 2.0
}, {
"week_ending": "2020-07-19",
"hours": 2.0
}]
}, {
"name": "Test activity 59",
"code": "D59",
"description": null,
"target": 15,
"weeks": [{
"week_ending": "2021-04-18",
"hours": 4.0
}, {
"week_ending": "2021-02-28",
"hours": 2.0
}, {
"week_ending": "2021-02-14",
"hours": 5.0
}, {
"week_ending": "2020-11-22",
"hours": 3.0
}, {
"week_ending": "2020-08-16",
"hours": 2.0
}]
}, ]
}, {
"year": "2019-2020",
"values": [{
"name": "Test activity 51",
"code": "D51",
"description": "Description goes here.",
"target": 40,
"weeks": [{
"week_ending": "2020-01-05",
"hours": 3.0
}, {
"week_ending": "2019-09-15",
"hours": 5.5
}, {
"week_ending": "2019-07-14",
"hours": 1.5
}]
}, {
"name": "Test activity 63",
"code": "D63",
"description": null,
"target": 15,
"weeks": [{
"week_ending": "2020-05-24",
"hours": 2.0
}, {
"week_ending": "2020-03-22",
"hours": 4.0
}, {
"week_ending": "2020-01-26",
"hours": 5.0
}, {
"week_ending": "2020-01-19",
"hours": 4.0
}, {
"week_ending": "2019-12-01",
"hours": 4.5
}, {
"week_ending": "2019-08-25",
"hours": 2.0
}, {
"week_ending": "2019-07-21",
"hours": 3.0
}]
}, {
"name": "Test activity 27",
"code": "D27",
"description": "Description goes here.",
"target": 30,
"weeks": [{
"week_ending": "2020-04-05",
"hours": 2.0
}, {
"week_ending": "2020-03-22",
"hours": 6.0
}, {
"week_ending": "2020-01-12",
"hours": 1.0
}]
}, {
"name": "Test activity 59",
"code": "D59",
"description": null,
"target": 18,
"weeks": [{
"week_ending": "2019-12-01",
"hours": 2.0
}, {
"week_ending": "2019-10-27",
"hours": 9.0
}, {
"week_ending": "2019-09-01",
"hours": 2.5
}]
}, ]
}, {
"year": "2018-2019",
"values": [{
"name": "Test activity 51",
"code": "D51",
"description": "Description goes here.",
"target": 40,
"weeks": [{
"week_ending": "2018-09-30",
"hours": 3.0
}]
}, {
"name": "Test activity 63",
"code": "D63",
"description": null,
"target": 30,
"weeks": [{
"week_ending": "2018-08-19",
"hours": 3.5
}, {
"week_ending": "2019-02-10",
"hours": 5.0
}, {
"week_ending": "2018-12-30",
"hours": 3.0
}, {
"week_ending": "2018-10-21",
"hours": 2.0
}, {
"week_ending": "2018-08-26",
"hours": 4.0
}]
}, {
"name": "Test activity 27",
"code": "D27",
"description": "Description goes here.",
"target": 25,
"weeks": [{
"week_ending": "2018-11-18",
"hours": 6.0
}, {
"week_ending": "2018-10-21",
"hours": 2.0
}, {
"week_ending": "2018-10-07",
"hours": 6.0
}]
}, {
"name": "Test activity 59",
"code": "D59",
"description": null,
"target": 20,
"weeks": [{
"week_ending": "2018-11-11",
"hours": 4.0
}, {
"week_ending": "2018-08-26",
"hours": 1.0
}, {
"week_ending": "2018-08-12",
"hours": 12.0
}]
}]
}]
最佳答案
对于 D3 nest
,您的要求太复杂了。除此之外,d3.nest
无论如何都将被弃用...因此,这是一种纯 JavaScript 方法。
我们首先得到一组独特的年份:
const yearsList = [...new Set(data.map(d => d.years.map(e => e.year)).flat())];
然后,有了这个集合,我们循环遍历您的数据并创建一个新数组(这里称为 newData
),在一个ad hoc 的解决方案中和冗长:
yearsList.forEach(d => {
data.forEach(e => {
const foundObject = e.years.find(f => f.year === d);
if (foundObject) {
const foundInNewData = newData.find(f => f.year === d);
const values = {
name: e.name,
code: e.code,
description: e.description,
target: foundObject.target,
weeks: foundObject.weeks
};
if (foundInNewData) {
foundInNewData.values.push(values);
} else {
newData.push({
year: d,
values: [values]
});
};
};
});
});
这是演示:
const data = [{
"id": 2,
"name": "Test activity 51",
"code": "D51",
"description": "Description goes here.",
"years": [{
"id": 8,
"year": "2020-2021",
"target": 65,
"weeks": [{
"week_ending": "2020-12-06",
"hours": 4.0
},
{
"week_ending": "2020-12-06",
"hours": 2.5
},
{
"week_ending": "2020-10-18",
"hours": 2.0
},
{
"week_ending": "2020-07-19",
"hours": 2.0
}
]
},
{
"id": 11,
"year": "2019-2020",
"target": 40,
"weeks": [{
"week_ending": "2020-01-05",
"hours": 3.0
},
{
"week_ending": "2019-09-15",
"hours": 5.5
},
{
"week_ending": "2019-07-14",
"hours": 1.5
}
]
},
{
"id": 10,
"year": "2018-2019",
"target": 40,
"weeks": [{
"week_ending": "2018-09-30",
"hours": 3.0
}]
}
]
},
{
"id": 3,
"name": "Test activity 63",
"code": "D63",
"description": null,
"years": [{
"id": 2,
"year": "2019-2020",
"target": 15,
"weeks": [{
"week_ending": "2020-05-24",
"hours": 2.0
},
{
"week_ending": "2020-03-22",
"hours": 4.0
},
{
"week_ending": "2020-01-26",
"hours": 5.0
},
{
"week_ending": "2020-01-19",
"hours": 4.0
},
{
"week_ending": "2019-12-01",
"hours": 4.5
},
{
"week_ending": "2019-08-25",
"hours": 2.0
},
{
"week_ending": "2019-07-21",
"hours": 3.0
}
]
},
{
"id": 9,
"year": "2018-2019",
"target": 30,
"weeks": [{
"week_ending": "2018-08-19",
"hours": 3.5
},
{
"week_ending": "2019-02-10",
"hours": 5.0
},
{
"week_ending": "2018-12-30",
"hours": 3.0
},
{
"week_ending": "2018-10-21",
"hours": 2.0
},
{
"week_ending": "2018-08-26",
"hours": 4.0
}
]
}
]
},
{
"id": 1,
"name": "Test activity 27",
"code": "D27",
"description": "Description goes here.",
"years": [{
"id": 4,
"year": "2019-2020",
"target": 30,
"weeks": [{
"week_ending": "2020-04-05",
"hours": 2.0
},
{
"week_ending": "2020-03-22",
"hours": 6.0
},
{
"week_ending": "2020-01-12",
"hours": 1.0
}
]
},
{
"id": 1,
"year": "2018-2019",
"target": 25,
"weeks": [{
"week_ending": "2018-11-18",
"hours": 6.0
},
{
"week_ending": "2018-10-21",
"hours": 2.0
},
{
"week_ending": "2018-10-07",
"hours": 6.0
}
]
}
]
},
{
"id": 10,
"name": "Test activity 59",
"code": "D59",
"description": null,
"years": [{
"id": 13,
"year": "2020-2021",
"target": 15,
"weeks": [{
"week_ending": "2021-04-18",
"hours": 4.0
},
{
"week_ending": "2021-02-28",
"hours": 2.0
},
{
"week_ending": "2021-02-14",
"hours": 5.0
},
{
"week_ending": "2020-11-22",
"hours": 3.0
},
{
"week_ending": "2020-08-16",
"hours": 2.0
}
]
},
{
"id": 14,
"year": "2019-2020",
"target": 18,
"weeks": [{
"week_ending": "2019-12-01",
"hours": 2.0
},
{
"week_ending": "2019-10-27",
"hours": 9.0
},
{
"week_ending": "2019-09-01",
"hours": 2.5
}
]
},
{
"id": 12,
"year": "2018-2019",
"target": 20,
"weeks": [{
"week_ending": "2018-11-11",
"hours": 4.0
},
{
"week_ending": "2018-08-26",
"hours": 1.0
},
{
"week_ending": "2018-08-12",
"hours": 12.0
}
]
}
]
}
];
const yearsList = [...new Set(data.map(d => d.years.map(e => e.year)).flat())];
const newData = [];
yearsList.forEach(d => {
data.forEach(e => {
const foundObject = e.years.find(f => f.year === d);
if (foundObject) {
const foundInNewData = newData.find(f => f.year === d);
const values = {
name: e.name,
code: e.code,
description: e.description,
target: foundObject.target,
weeks: foundObject.weeks
};
if (foundInNewData) {
foundInNewData.values.push(values)
} else {
newData.push({
year: d,
values: [values]
})
}
}
})
});
console.log(newData)
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/5.7.0/d3.min.js"></script>
您会注意到,上面的代码不仅有一两个循环,还有三个 循环。如果您的数据数组太大,您还可以尝试仅使用两个嵌套循环的解决方案:
const newData = [];
data.forEach(d => {
d.years.forEach(e => {
const foundInNewData = newData.find(f => f.year === e.year);
const values = {
name: d.name,
code: d.code,
description: d.description,
target: e.target,
weeks: e.weeks
};
if (foundInNewData) {
foundInNewData.values.push(values)
} else {
newData.push({
year: e.year,
values: [values]
})
}
});
});
这是相应的演示:
const data = [{
"id": 2,
"name": "Test activity 51",
"code": "D51",
"description": "Description goes here.",
"years": [{
"id": 8,
"year": "2020-2021",
"target": 65,
"weeks": [{
"week_ending": "2020-12-06",
"hours": 4.0
},
{
"week_ending": "2020-12-06",
"hours": 2.5
},
{
"week_ending": "2020-10-18",
"hours": 2.0
},
{
"week_ending": "2020-07-19",
"hours": 2.0
}
]
},
{
"id": 11,
"year": "2019-2020",
"target": 40,
"weeks": [{
"week_ending": "2020-01-05",
"hours": 3.0
},
{
"week_ending": "2019-09-15",
"hours": 5.5
},
{
"week_ending": "2019-07-14",
"hours": 1.5
}
]
},
{
"id": 10,
"year": "2018-2019",
"target": 40,
"weeks": [{
"week_ending": "2018-09-30",
"hours": 3.0
}]
}
]
},
{
"id": 3,
"name": "Test activity 63",
"code": "D63",
"description": null,
"years": [{
"id": 2,
"year": "2019-2020",
"target": 15,
"weeks": [{
"week_ending": "2020-05-24",
"hours": 2.0
},
{
"week_ending": "2020-03-22",
"hours": 4.0
},
{
"week_ending": "2020-01-26",
"hours": 5.0
},
{
"week_ending": "2020-01-19",
"hours": 4.0
},
{
"week_ending": "2019-12-01",
"hours": 4.5
},
{
"week_ending": "2019-08-25",
"hours": 2.0
},
{
"week_ending": "2019-07-21",
"hours": 3.0
}
]
},
{
"id": 9,
"year": "2018-2019",
"target": 30,
"weeks": [{
"week_ending": "2018-08-19",
"hours": 3.5
},
{
"week_ending": "2019-02-10",
"hours": 5.0
},
{
"week_ending": "2018-12-30",
"hours": 3.0
},
{
"week_ending": "2018-10-21",
"hours": 2.0
},
{
"week_ending": "2018-08-26",
"hours": 4.0
}
]
}
]
},
{
"id": 1,
"name": "Test activity 27",
"code": "D27",
"description": "Description goes here.",
"years": [{
"id": 4,
"year": "2019-2020",
"target": 30,
"weeks": [{
"week_ending": "2020-04-05",
"hours": 2.0
},
{
"week_ending": "2020-03-22",
"hours": 6.0
},
{
"week_ending": "2020-01-12",
"hours": 1.0
}
]
},
{
"id": 1,
"year": "2018-2019",
"target": 25,
"weeks": [{
"week_ending": "2018-11-18",
"hours": 6.0
},
{
"week_ending": "2018-10-21",
"hours": 2.0
},
{
"week_ending": "2018-10-07",
"hours": 6.0
}
]
}
]
},
{
"id": 10,
"name": "Test activity 59",
"code": "D59",
"description": null,
"years": [{
"id": 13,
"year": "2020-2021",
"target": 15,
"weeks": [{
"week_ending": "2021-04-18",
"hours": 4.0
},
{
"week_ending": "2021-02-28",
"hours": 2.0
},
{
"week_ending": "2021-02-14",
"hours": 5.0
},
{
"week_ending": "2020-11-22",
"hours": 3.0
},
{
"week_ending": "2020-08-16",
"hours": 2.0
}
]
},
{
"id": 14,
"year": "2019-2020",
"target": 18,
"weeks": [{
"week_ending": "2019-12-01",
"hours": 2.0
},
{
"week_ending": "2019-10-27",
"hours": 9.0
},
{
"week_ending": "2019-09-01",
"hours": 2.5
}
]
},
{
"id": 12,
"year": "2018-2019",
"target": 20,
"weeks": [{
"week_ending": "2018-11-11",
"hours": 4.0
},
{
"week_ending": "2018-08-26",
"hours": 1.0
},
{
"week_ending": "2018-08-12",
"hours": 12.0
}
]
}
]
}
];
const newData = [];
data.forEach(d => {
d.years.forEach(e => {
const foundInNewData = newData.find(f => f.year === e.year);
const values = {
name: d.name,
code: d.code,
description: d.description,
target: e.target,
weeks: e.weeks
};
if (foundInNewData) {
foundInNewData.values.push(values)
} else {
newData.push({
year: e.year,
values: [values]
})
}
});
});
console.log(newData)
关于javascript - 从 json 层次结构中较低的键嵌套或映射数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57949333/
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我已经用 Elasticsearch 玩了大约一天了,所以我非常陌生。我正在尝试 POST/import 一个简单的文件: { "compression" : "none", "com
enter image description here 在此示例中,要记录带有“title”和“director”键的属性值,使用 obj[key]。因为我们已经处于对象的执行上下文中:在本例中是电
我是新开类。 我使用新的电子邮件 ID 和密码在 openshift 上创建了一个项目。让我们称之为 firstApp 。我做了 rhc 设置和我的 ssh key 与我的项目相关联。 我的 frie
当我使用 Jackson 反序列化 json 字符串时,我通常不想创建所有 bean 类的属性,而且我只需要一些 json 字符串的字段,其他字段我不需要。所以我经常只在我需要的 java 类 bea
我想编写一个带有 keys/keys* 的规范,但能够内联值规范,但不支持 by design ,我明白了其背后的原因。然而,有时,本地图存在特定上下文时,您确实希望(或者只是通过遗留或第三方)键和值
my %fruit_colors = ("apple", "red", "banana", "yellow"); my @fruits = keys %fruit_colors; my @colors
我正在使用 vb.net 2008 和 DataGridView。我正在寻找允许我将 enter 键移动到右侧的下一列而不是在保持在同一列时向下移动一行的代码。 最佳答案 如果您正在确认编辑,只需移动
我刚刚开始学习编码,我遇到了这个我无法理解的问题。 “我们将添加的第二个函数称为搜索,它将以名字作为参数。它将尝试将收到的名字与我们 friend 联系人列表中的任何名字相匹配。如果它找到匹配项,就会
我已经在 Python 中运行了下面的代码,以从文本文件中生成单词列表及其计数。我该如何从“Frequency_list”变量中过滤掉计数为 1 的单词? 另外,如何将底部的打印语句循环导出到CSV
我正在尝试 XSLT 中的查找表示例,但无法使其正常工作
是否可以在 Javascript/Typescript 中编写一个将参数名称/键作为字符串返回的函数? function foo(arg) {...} let user = new User(); f
我正在尝试创建一个带有键/值的对象,但是当我看到该对象时,键没有正确填充.. 我希望键是 - 0,1,2,3 但它显示“索引”作为键。 > categories = ["09/07/2016 00:0
将 Android Studio 从 1.5 升级到 2.0 后,模拟器(现在版本为 25.1.1,我在其上配置了模拟硬件键盘)不再将 [Esc] 键识别为等同于 [Back] 按钮。 如何恢复这个有
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