javascript - 如何避免使用 OnChange 和 Marketo 加载表单

Question

我有一个带有“onchange”功能的下拉列表，用于根据用户输入加载 Marketo 表单。表单加载正确，除了当用户最初选择“需要新产品”然后切换到“需要支持”(或反之亦然)时，“产品表单”不会消失。取而代之的是，“产品表格”保留下来，另外加载“需要支持”表格(在产品表格下方)。用户可以多次切换/触发，从而产生许多额外的形式，这是一个问题!

我需要帮助调整代码，以便始终只加载一个表单，并且当用户触发器时，用户选择的先前表单不再存在。有帮助吗？？谢谢!

<script src="//app-e.marketo.com/js/forms2/js/forms2.js"></script>

<p>How can we help?</p>
<select id="mySelect" onchange="myFunction()">
  <option value="default">--please select a reason--</option>
  <option value="product">Need a new product</option>
  <option value="support">Need support</option>
</select>


<p id="demo"></p>
<script>
function myFunction() {
    var x = document.getElementById("mySelect").value;
    document.getElementById("demo").innerHTML = "You selected: " + x;
    if (x == "product") {
        MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber", *uniquenumber);
    }
    else if (x == "support") {
        MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber2", *uniquenumber2);
    }
}
</script>

<form id="mktoForm_*uniquenumber1"></form>
<form id="mktoForm_*uniquenumber2"></form>

Answer 1

我推荐以下内容:

1. 实现一种检查 Marketo 表单是否已加载的方法。例如:

   //Checks for element that matches "mktoForm_". If match, variable returns id of element. If no match, variable returns undefined. 
   var y = document.querySelector('[id^=mktoForm_]').id;
   

2. 实现一种删除 Marketo 表单的方法。例如:

   //jQuery implementation to remove form element
   $( "form" ).remove();
   

3. 实现条件逻辑以确定当前状态。例如:

   if (x == "product" && y === undefined) {
       MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber", *uniquenumber);
   }
   else if (x == "product" && y != undefined) {
       //jQuery implementation to remove form element
       $( "form" ).remove();
       MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber2", *uniquenumber2);
   }
   else if (x == "support" && y === undefined) {
       MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber2", *uniquenumber2);
   }
   else (x == "support" && y != undefined) {
       //jQuery implementation to remove form element
       $( "form" ).remove();
       MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber2", *uniquenumber2);
   }
   

这是一个可能的实现:

<script>
function myFunction() {
    var x = document.getElementById("mySelect").value;
    //Checks for element that matches "mktoForm_". If no match, variable returns undefined. 
    var y = document.querySelector('[id^=mktoForm_]').id;
    document.getElementById("demo").innerHTML = "You selected: " + x;

    if (x == "product" && y === undefined) {
        MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber", *uniquenumber);
    }
    else if (x == "product" && y != undefined) {
        //jQuery implementation to remove form element
        $( "form" ).remove();
        MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber2", *uniquenumber2);
    }
    else if (x == "support" && y === undefined) {
        MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber2", *uniquenumber2);
    }
    else (x == "support" && y != undefined) {
        //jQuery implementation to remove form element
        $( "form" ).remove();
        MktoForms2.loadForm("//app-e.marketo.com", "*uniquenumber2", *uniquenumber2);
    }
}
</script>