javascript - 从里面获取js文件查询参数

Question

我用这样的查询参数加载这个文件:
<strong>src='somefile.js?userId=123'</strong>

我在读取“userId”查询参数的“somefile.js”文件中编写了以下函数
但我觉得这不是最好的方法。坦率地说，它非常丑陋。 有没有更好的办法？

function getId(){
   var scripts = document.getElementsByTagName('script'), script;
   for(var i in scripts){
        if( scripts.hasOwnProperty(i) && scripts[i].src.indexOf('somefile.js') != -1 )
            var script = scripts[i];
   }

    var s = (script.getAttribute.length !== undefined) ? 
        script.getAttribute('src') : 
        script.getAttribute('src', 2);

   return getQueryParams('userId',s);
};

Answer 1

// extracts the params from the currently running (external) script
var getScriptQp = (function(){
    var scripts = document.getElementsByTagName('script');
    var this_script_tag = scripts[scripts.length - 1]; //script tag of this file

    if( typeof this_script_tag != undefined && this_script_tag.src )
        var s = this_script_tag.src;
    else{
        return this.customer;
    }
    return s;
})();

// gets the Query Params of a givver query string
function getQueryParam(name, query){
    name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
    var regexS = "[\\?&]" + name + "=([^&#]*)";
    var regex = new RegExp(regexS);
    var results = regex.exec(query);
    if (results == null)
        return "";
    else
        return results[1];
}

getQueryParam( 'param',getScriptQp );