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javascript - 在 iOS 中将字符串传递给 JavaScript 无法获取调用的函数

转载 作者:塔克拉玛干 更新时间:2023-11-02 20:16:14 24 4
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花了整个晚上谷歌搜索这个,仍然没有骰子。我只是想将一个字符串传递给嵌入式 html/javascript 测试文件。我没有收到任何错误,但我也没有收到任何调用的函数:[

这是我在代码方面得到的:

详细 Controller .h

#import <UIKit/UIKit.h>

@interface DetailController : UIViewController<UIWebViewDelegate>{
UIWebView *webView;
}


@property (nonatomic, strong) NSArray *Detailinfo;
@property (nonatomic, strong) IBOutlet UILabel *DetailName;
@property (nonatomic, strong) IBOutlet UILabel *dob;
@property (nonatomic, retain) IBOutlet UIWebView *webView;


@end

详细 Controller .m

#import "DetailController.h"

@interface DetailController ()


@end

@implementation DetailController
@synthesize webView;

- (id)initWithNibName:(NSString *)nibNameOrNil bundle:(NSBundle *)nibBundleOrNil
{
self = [super initWithNibName:nibNameOrNil bundle:nibBundleOrNil];
if (self) {
// Custom initialization
}
return self;
}

- (void)viewDidLoad
{
[super viewDidLoad];




// Do any additional setup after loading the view.
self.navigationItem.hidesBackButton = YES;
UINavigationItem *topBar;
topBar.title = self.Detailinfo[0];
self.DetailName.text = self.Detailinfo[0];
self.dob.text = self.Detailinfo[1];


NSURL *url = [NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource:@"javascriptTest" ofType:@"html"]];
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
[self.webView loadRequest:requestObj];
self.webView.delegate = self;

}

- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}

-(void)webViewDidFinishLoad:(UIWebView *)webView{

[self.webView stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@"loadText(%@)", self.Detailinfo[1]]];

}





@end

和 HTML 文件 javascriptTest.html

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Test JavaScript</title>
<script>
function loadText(txtString)
{
var divd = document.createElement('div');
divd.innerHTML = "<p>" + txtString + "</p>";
document.body.appendChild(divd);
document.getElementById('info').value = "";
}
</script>
</head>
<body>
loaded
<!--
<input type="text" id="info" />
<button onclick="loadText(document.getElementById('info').value)"> Load Text </button>
-->
</body>
</html>

非常感谢任何帮助:]

更新正如@ACB所说,只需要在javascript函数中添加'' @"loadText('%@')"

最佳答案

你需要改变,

@"loadText(%@)"

@"loadText('%@')"

由于您将字符串传递给此 javascript 函数,因此它应该在引号内。

正如 Fabio 所说,如果字符串中包含任何 ",您可能必须对字符串进行转义。

关于javascript - 在 iOS 中将字符串传递给 JavaScript 无法获取调用的函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14723916/

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