android - 在 android 中使用短信管理器发送短信时返回 RESULT_ERROR_GENERIC_FAILURE

Question

我正在使用短信管理器向多个用户发送短信，但出现 RESULT_ERROR_GENERIC_FAILURE(一般性故障)。如何解决此问题？

// ---sends an SMS message to another device---
private void sendSMS(String phoneNumber, String message) {
    String SENT = "SMS_SENT";
    String DELIVERED = "SMS_DELIVERED";

    PendingIntent sentPI = PendingIntent.getBroadcast(this, 0, new Intent(
            SENT), 0);

    PendingIntent deliveredPI = PendingIntent.getBroadcast(this, 0,
            new Intent(DELIVERED), 0);

    // ---when the SMS has been sent---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(getBaseContext(), "SMS sent",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_GENERIC_FAILURE:
                Toast.makeText(getBaseContext(), "Generic failure",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NO_SERVICE:
                Toast.makeText(getBaseContext(), "No service",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_NULL_PDU:
                Toast.makeText(getBaseContext(), "Null PDU",
                        Toast.LENGTH_SHORT).show();
                break;
            case SmsManager.RESULT_ERROR_RADIO_OFF:
                Toast.makeText(getBaseContext(), "Radio off",
                        Toast.LENGTH_SHORT).show();
                break;
            }
        }
    }, new IntentFilter(SENT));

    // ---when the SMS has been delivered---
    registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context arg0, Intent arg1) {
            switch (getResultCode()) {
            case Activity.RESULT_OK:
                Toast.makeText(getBaseContext(), "SMS delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            case Activity.RESULT_CANCELED:
                Toast.makeText(getBaseContext(), "SMS not delivered",
                        Toast.LENGTH_SHORT).show();
                break;
            }
        }
    }, new IntentFilter(DELIVERED));

    SmsManager sms = SmsManager.getDefault();
    sms.sendTextMessage(phoneNumber, null, message, sentPI, deliveredPI);
}

这里我使用 SmsManager 和 sendSms() 将数字和消息作为参数。

Answer 1

也许你应该缩短你的短信正文以适应只有 1 条短信(只有 160 个字符)，我使用了相同的代码并得到了完全相同的错误＆当我将短信缩短到 160 以下时，它已成功发送: )