ios - 根据 NSDictionaries 的 NSArray 中的值为 UITableView 创建索引

Question

我在从包含许多 NSDictionaries 的 NSArray 创建索引时遇到问题，我想在其中仅基于 username 索引值字典中的关键字。例如，每个词典看起来像这样:

{
     username => "daspianist", //<- Only want to use this value to create index
     objectId => "hjd72h3jd",
     createdAt => "30-1-2014",
     updatedAt => "30-1-2014"
}

目前我已经简化了这个问题，所以我正在索引 NSStrings 的 NSArray，我所做的是:

//Note that `stringArray` is passed to this method
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
    for (char firstChar = 'a'; firstChar <= 'z'; firstChar++)
    {
        NSString *firstCharacter = [NSString stringWithFormat:@"%c", firstChar];
        NSArray *content = [stringArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"SELF beginswith[cd] %@", firstCharacter]];
        NSMutableArray *mutableContent = [NSMutableArray arrayWithArray:content];

        if ([mutableContent count] > 0)
        {
            NSString *key = [firstCharacter uppercaseString];
            [dict setObject:mutableContent forKey:key];
            NSLog(@"%@: %u", key, [mutableContent count]);
        }
    }

我正在努力将我一直在为 NSStrings 所做的事情转换为我的 NSDictionaries 中 username 键的值，并希望得到任何指导。谢谢!

更新

澄清一下，我感兴趣的结果字典看起来像这样

{
    "a" => {
             username => "aardvark",
             otherKeys => "otherValues"
           },
           {
             username => "applepicking",
             otherKeys => "otherValues"
           }
    "d" => {
             username => "daspianist",
             otherKeys => "otherValues"
           }
      ....
}

更新 2

根据Wain的答案打出来的解决方案，方便使用:

 NSMutableDictionary *dict = [NSMutableDictionary dictionary];
    for (char firstChar = 'a'; firstChar <= 'z'; firstChar++)
    {
        NSString *firstCharacter = [NSString stringWithFormat:@"%c", firstChar];
        NSArray *content = [userNamesArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"SELF beginswith[cd] %@", firstCharacter]];
        NSMutableArray *mutableContent = [NSMutableArray arrayWithArray:content];
        NSPredicate *p = [NSPredicate predicateWithFormat:@"username IN %@", content];

        if ([mutableContent count] > 0)
        {
            NSString *key = [firstCharacter uppercaseString];
            NSArray *values = [originalDictionary filteredArrayUsingPredicate:p];
            [dict setObject:values forKey:key];
            NSLog(@"%@: %lu", key, (unsigned long)[mutableContent count]);
        }
    }

    NSLog(@"The dictionary is %@", dict);

Answer 1

因此，content 是与当前键匹配的 username 的数组。目标是在该数组中找到所有包含 username 的字典。这是谓词的工作:

NSPredicate *p = [NSPredicate predicateWithFormat:@"username IN %@", content];

现在你可以:

NSArray *values = [dictArray filteredArrayUsingPredicate:p];
[dict setObject:values forKey:key];