ios - JSON 解析 UITableViewController

Question

我正在尝试将我的 JSON 数据传递到 UITableViewController。我确实设法将我的一个 JSON 传递到 UITableView 并在用户执行操作时将其显示在下一个 ViewController 上。问题是我得到了 4 个 JSON 数据，我希望它显示在 ViewController 上。由于我的 JSON 格式，我无法执行 ObjectForKey。

这是我的 JSON

{
    uid: "60",
    name: "pae1344",
    mail: "viper1344@gmail.com",
    theme: "",
    signature: "",
    signature_format: "plain_text",
    created: "1396189622",
    access: "0",
    login: "1396189622",
    status: "1",
    timezone: "Asia/Bangkok",
    language: "",
    picture: "0",
    init: "viper1344@gmail.com",
    data: null,
    uri: "http://localhost/drupal/rest/user/60"
},

这是来自 myTableViewController 的代码。

#import "TestinViewController.h"
#import "AFNetworking.h"
#import "TestinCell.h"
#import "EDscriptionViewController.h"
@interface TestinViewController ()

@end

@implementation TestinViewController

- (id)initWithStyle:(UITableViewStyle)style
{
    self = [super initWithStyle:style];
    if (self) {
        // Custom initialization
    }
    return self;
}

- (void)viewDidLoad
{
    [super viewDidLoad];
    self.finishedGooglePlacesArray = [[NSArray alloc] init];
    [self makeRestuarantsRequests];

    // Uncomment the following line to preserve selection between presentations.
    // self.clearsSelectionOnViewWillAppear = NO;

    // Uncomment the following line to display an Edit button in the navigation bar for this view controller.
    // self.navigationItem.rightBarButtonItem = self.editButtonItem;
}

- (void)didReceiveMemoryWarning
{
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}
-(void)makeRestuarantsRequests
{
    NSURL *url = [NSURL URLWithString:@"http://localhost/drupal/rest/enterpriselist.json"];

    NSURLRequest *request = [NSURLRequest requestWithURL:url];

    AFJSONRequestOperation *operation = [AFJSONRequestOperation
                                         JSONRequestOperationWithRequest:request
                                         success:^(NSURLRequest *request, NSHTTPURLResponse *response, id responseObject)
                                         {

                                             self.googlePlacesArrayFromAFNetworking = [responseObject valueForKey:@"node_title"];
                                             self.body = [responseObject valueForKey:@"Body"];
                                             self.tel = [responseObject valueForKey:@"Enterprise Tel"];
                                             self.mail = [responseObject valueForKey:@"Enterprise email"];

                                              [self.tableView reloadData];
                                             NSLog(@"%@", self.googlePlacesArrayFromAFNetworking);
                                             NSLog(@"%@" , self.body);
                                             NSLog(@"%@", self.tel);
                                             NSLog(@"%@", self.mail);
                                         }
                                         failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id responseObject)
                                         {
                                             NSLog(@"Request Failed with Error: %@, %@", error, error.userInfo);
                                         }];

    [operation start];

}
#pragma mark - Table view data source

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
#warning Potentially incomplete method implementation.
    // Return the number of sections.
    return 1;
}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
#warning Incomplete method implementation.
    // Return the number of rows in the section.
    return [self.googlePlacesArrayFromAFNetworking count];
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
    static NSString *CellIdentifier = @"Cell";
    TestinCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
    if (cell ==Nil){
        cell = [[TestinCell alloc]initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
    }
    cell.txtEnterPriseName.text = [self.googlePlacesArrayFromAFNetworking objectAtIndex:indexPath.row];
    cell.txtEnterPriseBody.text = [self.body objectAtIndex:indexPath.row];
    cell.txtEnterPriseEmail.text = [self.mail objectAtIndex:indexPath.row];
    cell.txtEnterPriseTel.text = [self.tel objectAtIndex:indexPath.row];
    // Configure the cell...

    return cell;
}
-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{

        NSIndexPath * indexPath = [self.tableView indexPathForSelectedRow];
        EDscriptionViewController *destViewController = (EDscriptionViewController*) segue.destinationViewController ;
        //     destViewController.enterprise = [enterPrise_names objectAtIndex:indexPath.row];
        destViewController.detail = [self.googlePlacesArrayFromAFNetworking objectAtIndex:indexPath.row];


    destViewController.Ebody = [self.body objectAtIndex:indexPath.row];
    destViewController.EEmail = [self.mail objectAtIndex:indexPath.row];
    destViewController.ETel = [self.tel objectAtIndex:indexPath.row];
    //    destViewController.ebody = [self.body objectAtIndex:indexPath.row];
//    destViewController.etel = [self.tel objectAtIndex:indexPath.row];
//    destViewController.email = [self.mail objectAtIndex:indexPath.row];
//    


}

有没有办法让我将 JSON 变成一个字典，这样我就可以使用 ObjectForKey 选择要显示的内容？

Answer 1

首先通过将 .m 和 .h 文件添加到您的项目来使用此库:

JSONKit

然后你可以将 JSON 字符串转换成字典。

//JSONString is a NSString variable with the JSON
NSDictionary *myJSONDic = [JSONString objectFromJSONString]
NSLog(@"User Id is : %@",[myJSONDic valueForKey:@"uid"]);