java - 从字符串解析时间范围

Question

我找不到我的确切问题的答案，所以就这样吧......假设我有一个字符串数组，我想像这样将其转换为 24 小时制时间值:

String[] strings = {"12:04 am", "12:04 pm"};
System.out.println("Pick-up Times: ");
for (String i: strings) 
    System.out.println(i);
System.out.println();

DateFormat format = new SimpleDateFormat("hh:mm a");

System.out.println("Converted to 24-Hour format: ");
for (String i: strings) {
    Date date = format.parse(i);        
    Time time = new Time(date.getTime());
    System.out.println(time);
}

输出:

Pick-up Times:
12:04 am
12:04 pm

Converted to 24-Hour format:
00:04:00
12:04:00

效果很好，但假设我的范围是 12:00 pm - 12:10 pm:

String[] strings = {"12:00 pm - 12:10 pm"};
System.out.println("Pick-up Times: ");
for (String i: strings) 
    System.out.println(i);
System.out.println();

DateFormat format = new SimpleDateFormat("hh:mm a");

System.out.println("Converted to 24-Hour format: ");
for (String i: strings) {
    Date date = format.parse(i);        
    Time time = new Time(date.getTime());
    System.out.println(time);
}

这是我的输出:

Pick-up Times:
12:00 pm - 12:10 pm

Converted to 24-Hour format:
12:00:00

我试过像这样更改 SimpleDateFormat:

DateFormat format = new SimpleDateFormat("hh:mm a - hh:mm a");

结果很有趣:

Pick-up Times:
12:00 pm - 12:10 pm

Converted to 24-Hour format:
12:10:00

我要找的结果是:

Pick-up Times:
12:00 pm - 12:10 pm

Converted to 24-Hour format:
12:00:00 - 12:10:00

有什么想法吗？

Answer 1

好吧，如果问题是关于范围的，你可以把它分开。我会给你几行代码，这样你就可以根据自己的代码进行调整:

String s = {"ABC - aaa - eee - ccc"};
String arr[] = s.split(" - ");
for(String str: arr)
    SYstem.out.println(str);

您可以使用字符串代替。