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java - 为休息服务实现 JUnit 测试

转载 作者:塔克拉玛干 更新时间:2023-11-02 19:51:36 24 4
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我必须为我的其余服务实现一些 JUnit 测试。例如,这是我的一项休息服务:

@Path("/dni-fe")
public class HelloWorld
{

@POST
@Path("/home")
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)

public MachineResponse doMachineRegister(MachineBean machineBean)
{
MachineResponse response = new MachineResponse();
String name = machineBean.getName();
String country = machineBean.getCountry();
String company = machineBean.getCompany();
String model = machineBean.getModel();

//make some stuff and some queries on db to populate the response object
return response;
}

这是我对这项服务的测试:

public class MachineResponseTest {

private static final String BASE_URI = "http://localhost:8080/dni-fe/home"

@Test
public void testDevice() {

WebResource resource = Client.create().resource(BASE_URI);
resource.accept(MediaType.APPLICATION_JSON);

StringBuilder sb = new StringBuilder();
sb.append("{\"name\":\"123456\",\n");
sb.append(" \"country\":\"Spain\",\n");
sb.append(" \"company\":\"xxx\",\n");
sb.append(" \"model\":\"1.10.0\"\n}");

MachineResponse result = resource.post(MachineResponse.class,sb.toString());
}

测试失败,出现以下错误:

com.sun.jersey.api.client.UniformInterfaceException: POST http://localhost:8080/dni-fe/home returned a response status of 415 Unsupported Media Type at com.sun.jersey.api.client.WebResource.handle(WebResource.java:686)

最佳答案

我很确定你必须使用 .type(MediaType.APPLICATION_JSON),而不是 .accept(

关于java - 为休息服务实现 JUnit 测试,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41469143/

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