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java - Jax-ws异常序列化失败

转载 作者:塔克拉玛干 更新时间:2023-11-02 19:49:28 51 4
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我也面临着找不到解决方案的问题(或者我处理的方式不对)。当我的服务产生某些异常时,序列化似乎失败了。这会导致出现一个包装异常,这很痛苦,因为调用客户端会收到一个糟糕的错误,我想我正在从原始异常中丢失有用的信息。

在下面的示例中,它是一个 S3 存储桶访问问题,但我遇到了一些 SQL 异常的类似问题。

如果我能保留我的直接干预服务,那将很有用。理想的是添加一些自定义异常序列化代码。

> com.amazonaws.services.simpleworkflow.flow.DataConverterException:
> Failure serializing
> "com.sun.xml.internal.ws.fault.ServerSOAPFaultException: Client
> received SOAP Fault from server: Access Denied (Service: Amazon S3;
> Status Code: 403; Error Code: AccessDenied; Request ID: AAAAAAAAAAAA)
> Please see the server log to find more detail regarding exact cause of
> the failure." of type "class
> com.sun.xml.internal.ws.fault.ServerSOAPFaultException" when mapping
> key "null" at
> com.amazonaws.services.simpleworkflow.flow.JsonDataConverter.throwDataConverterException(JsonDataConverter.java:90)
> at
> com.amazonaws.services.simpleworkflow.flow.JsonDataConverter.toData(JsonDataConverter.java:78)
> at
> com.amazonaws.services.simpleworkflow.flow.pojo.POJOActivityImplementation.throwActivityFailureException(POJOActivityImplementation.java:102)
> at
> com.amazonaws.services.simpleworkflow.flow.pojo.POJOActivityImplementation.execute(POJOActivityImplementation.java:67)
> at
> com.amazonaws.services.simpleworkflow.flow.generic.ActivityImplementationBase.execute(ActivityImplementationBase.java:46)
> at
> com.amazonaws.services.simpleworkflow.flow.worker.SynchronousActivityTaskPoller.execute(SynchronousActivityTaskPoller.java:196)
> at
> com.amazonaws.services.simpleworkflow.flow.worker.ActivityTaskPoller$2.run(ActivityTaskPoller.java:92)
> at
> java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
> at
> java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
> at java.lang.Thread.run(Thread.java:748) Caused by:
> com.fasterxml.jackson.databind.JsonMappingException: Type id handling
> not implemented for type org.w3c.dom.Node (by serializer of type
> com.fasterxml.jackson.databind.ext.DOMSerializer) (through reference
> chain:
> com.sun.xml.internal.ws.fault.ServerSOAPFaultException["fault"]) at
> com.fasterxml.jackson.databind.SerializerProvider.mappingException(SerializerProvider.java:1084)
> at
> com.fasterxml.jackson.databind.JsonSerializer.serializeWithType(JsonSerializer.java:159)
> at
> com.fasterxml.jackson.databind.ser.BeanPropertyWriter.serializeAsField(BeanPropertyWriter.java:695)
> at
> com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:675)
> at
> com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeWithType(BeanSerializerBase.java:566)
> at
> com.fasterxml.jackson.databind.ser.impl.TypeWrappedSerializer.serialize(TypeWrappedSerializer.java:32)
> at
> com.fasterxml.jackson.databind.ser.DefaultSerializerProvider.serializeValue(DefaultSerializerProvider.java:130)
> at
> com.fasterxml.jackson.databind.ObjectMapper._configAndWriteValue(ObjectMapper.java:3559)
> at
> com.fasterxml.jackson.databind.ObjectMapper.writeValueAsString(ObjectMapper.java:2927)
> at
> com.amazonaws.services.simpleworkflow.flow.JsonDataConverter.toData(JsonDataConverter.java:72)
> ... 8 more

谢谢你的建议

最佳答案

Jackson 正在尝试序列化 com.sun.xml.internal.ws.fault.ServerSOAPFaultException 的一些实例.此异常是 javax.xml.ws.soap.SOAPFaultException 的子类,这happens to have a getter for retrieving the SOAPFault .由于 SOAPFault 是 DOM Node,Jackson 决定使用 DOMSerializer 并对类型信息进行编码,以便在反序列化时可以找出哪个具体类型 fault 是一个实例。问题是 DOMSerializer 不支持这种类型信息的东西,所以你得到 com.fasterxml.jackson.databind.JsonMappingException

我认为解决此问题的最佳方法是为 SOAPFault 注册一个自定义序列化器/反序列化器对。然后,您可以序列化为 String,并通过 SOAPFactory.createFault(...) methods 之一反序列化创建新实例。 .不要忘记还实现 JsonSerializer.serializeWithType(...) 以便 Jackson 可以正确地进行类型处理。

一个(非常粗糙的)草稿是

public class SOAPFaultSerializer extends StdSerializer<SOAPFault> {

public SOAPFaultSerializer() {
this(null);
}

public SOAPFaultSerializer(Class<SOAPFault> t) {
super(t);
}

@Override
public void serialize(SOAPFault fault, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonProcessingException {

jgen.writeStartObject();
// serialize "interesting" SOAPFault information
jgen.writeStringField("faultActor", fault.getFaultActor());
jgen.writeStringField("faultCode", fault.getFaultCode());
...
jgen.writeEndObject();
}

@Override
public void serializeWithType(JsonGenerator jgen, SerializerProvider provider, TypeSerializer typeSer) throws IOException, JsonGenerationException {
typeSer.writeTypePrefixForObject(this, jgen, SOAPFault.class);
serialize(value, jgen, provider);
typeSer.writeTypeSuffixForObject(this, jgen);
}
}

public class SOAPFaultDeserializer extends StdDeserializer<SOAPFault> {

public SOAPFaultDeserializer() {
this(null);
}

public SOAPFaultDeserializer(Class<?> vc) {
super(vc);
}

@Override
public SOAPFault deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException, JsonProcessingException {
JsonNode node = jp.getCodec().readTree(jp);
// deserialize "interesting" SOAPFault information
String faultActor = node.get("faultActor").asText();
String faultCode = node.get("faultCode").asText();
...
SOAPFactory factory = SOAPFactory.newInstance();
SOAPFault fault = factory.createFault();
// fill in SOAPFault with deserialized fields
fault.setFaultActor(faultActor);
fault.setFaultCode(faultCode);
...
return fault;
}
}

关于java - Jax-ws异常序列化失败,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46195359/

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