java - 使用@ControllerAdvice 和@ResponseStatus 更改响应状态代码

Question

我正在使用 spring mvc，我使用全局异常处理程序来处理异常

@ControllerAdvice
public class GlobalControllerExceptionHandler {

    @ResponseStatus(value = HttpStatus.CONFLICT, reason = "Data integrity violation")
    @ExceptionHandler({DataIntegrityViolationException.class})
    public @ResponseBody AdminResponse handleConflict(DataIntegrityViolationException ex,HttpServletResponse httpServletResponse) {

        AdminResponse error = new AdminResponse ();

        httpServletResponse.setStatus(HttpStatus.CONFLICT.value());
        error.setStatus(Status.FAILURE);
        error.setErrorDescription(ex.getMessage());

        return error;
    }

据我所知，注释 @ResponseStatus(value = HttpStatus.CONFLICT 会将 repose 状态代码更改为 HttpStatus.CONFLICT，但这并没有发生。当我创建虚拟异常并用 @ResponseStatus 注释这个虚拟异常然后抛出这个新异常时，GlobalControllerExceptionHandler 捕获并处理异常并更改响应状态代码。

如何在不创建新异常的情况下更改响应状态代码，我只需要捕获 DataIntegrityViolationException

Answer 1

你采取两种方式。

<强>1。使用@ResponseBody 并返回自定义 JSON 字符串。

@ExceptionHandler(value = { HttpClientErrorException.class, HTTPException.class })
public @ResponseBody String checkHTTPException(HttpServletRequest req, Exception exception,
        HttpServletResponse resp) throws JsonProcessingException {

    ObjectMapper mapper = new ObjectMapper();
    CommonExceptionModel model = new CommonExceptionModel();

    model.setMessage("400 Bad Request");
    model.setCode(HttpStatus.BAD_REQUEST.toString());

    String commonExceptionString = mapper.writeValueAsString(model);

    return commonExceptionString;
}

<强>2。使用 ResponseEntity 和异常

返回响应实体。

ResponseEntity.status(exception.getStatusCode()).headers(exception.getResponseHeaders())
                            .body(exception.getResponseBodyAsString());