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java - Spring JPA @Query注解,SQL地理定位错误

转载 作者:塔克拉玛干 更新时间:2023-11-02 19:46:08 26 4
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我正在尝试使用 MariaDB 10.0.36(带有 innodb 引擎)和 Spring Data,通过基于地理位置的 native 查询获取表条目。

这是我的方法签名:

@Query(value = "SELECT j "
+ "FROM Car j "
+ "WHERE distance(j.localization.point, POINT((?2), (?3))) AS sdistance < 10 "
+ "AND (j.name LIKE %?1% "
+ "OR j.carCategory.name LIKE %?1% "
+ "OR j.description LIKE %?1%) "
+ "ORDER BY sdistance "
+ "LIMIT 25", nativeQuery = true)
List<Car> getNearestCars(String text, double lat, double lon);

这是我的本地化实体:

@Entity
@Table(name = "localizations")
public class Localization {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private long id;
@OneToOne(fetch = FetchType.LAZY)
private User assossiatedUser;
private String zipCode;
private String state;
@Column(length=200)
private String city;
@Column(length=200)
private String number;
@Column(length=200)
private String neighbourhood;
@Column(length=16)
private String publicPlaceType;
@Column(length=200)
private String publicPlace;
@Column(length=200)
private String complement;
private double coordX;
private double coordY;
@Column(columnDefinition = "POINT")
private Point point;
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public User getAssossiatedUser() {
return assossiatedUser;
}
public void setAssossiatedUser(User assossiatedUser) {
this.assossiatedUser = assossiatedUser;
}
public String getZipCode() {
return zipCode;
}
public void setZipCode(String zipCode) {
this.zipCode = zipCode;
}
public String getState() {
return state;
}
public void setState(String state) {
this.state = state;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
public String getComplement() {
return complement;
}
public void setComplement(String complement) {
this.complement = complement;
}
public double getCoordX() {
return coordX;
}
public void setCoordX(double coordX) {
this.coordX = coordX;
}
public double getCoordY() {
return coordY;
}
public void setCoordY(double coordY) {
this.coordY = coordY;
}
public String getNeighbourhood() {
return neighbourhood;
}
public void setNeighbourhood(String neighbourhood) {
this.neighbourhood = neighbourhood;
}
public String getPublicPlaceType() {
return publicPlaceType;
}
public void setPublicPlaceType(String publicPlaceType) {
this.publicPlaceType = publicPlaceType;
}
public String getNumber() {
return number;
}
public void setNumber(String number) {
this.number = number;
}
public String getPublicPlace() {
return publicPlace;
}
public void setPublicPlace(String publicPlace) {
this.publicPlace = publicPlace;
}
public Point getPoint() {
return point;
}
public void setPoint(Point point) {
this.point = point;
}
}

我使用以下命令创建函数距离(位于 https://www.scribd.com/presentation/2569355/Geo-Distance-Search-with-MySQL ):

DELIMITER $$

CREATE FUNCTION `distance`(a POINT, b POINT) RETURNS double DETERMINISTIC
BEGIN
DECLARE d double;
SET d = round(glength(linestringfromwkb(linestring(asbinary(a),asbinary(b)))));
RETURN d;
END $$

DELIMITER ;

这是 application.yml:

server.port: 8080
server.context-path: /api
enter code here

spring:
datasource:
url: jdbc:mariadb://localhost:3306/databasename
driverClassName: org.mariadb.jdbc.Driver
username: root
password: root
jpa:
hibernate:
ddl-auto: create
dialect: org.hibernate.dialect.MySQL5InnoDBDialect
hbm2ddl.auto: update
show_sql: false

logging:
level:
org.springframework: ERROR

当我访问方法 getNearestJobs 时,出现以下错误:

org.mariadb.jdbc.internal.util.dao.QueryException: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'AS sdistance < 10 AND (j.name LIKE '%eteste10%' OR j.jobCategory.name LIKE '%ete' at line 1 Query is: SELECT j FROM Job j WHERE distance(j.localization.point, POINT((?), (?))) AS sdistance < 10 AND (j.name LIKE ? OR j.jobCategory.name LIKE ? OR j.description LIKE ?) ORDER BY sdistance LIMIT 25, parameters [-5.1797161,-40.6646966,'%eteste10%','%eteste10%','%eteste10%']

我做错了什么?

最佳答案

我明白了。 sql查询有两个问题:第一,如果使用原生查询,显然不能使用面向对象抽象;其次,sdistance 应该在 SELECT 子句而不是 WHERE/HAVING 子句中声明。

@Query(value = "SELECT *, distance(l.point, POINT((?2), (?3))) AS jdistance "
+ "FROM cars j, car_categories c, localizations l "
+ "WHERE (j.name LIKE %?1% "
+ "OR j.description LIKE %?1% "
+ "OR (j.car_category_id = c.id AND c.name LIKE %?1%)) "
+ "AND l.id = j.localization_id "
+ "HAVING jdistance < 10 "
+ "ORDER BY jdistance"
, nativeQuery = true)
List<Car> getNearestCars(String text, double lat, double lon);

关于java - Spring JPA @Query注解,SQL地理定位错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53509179/

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