java - 基本 Java 刽子手

Question

我刚刚开始学习 Java 作为我的第一门编程语言。

在类里面，我们被分配使用 while 和 for 循环制作一个基本的 Hangman 游戏。

到目前为止我有什么

当用户输入第一个猜测时，它确实识别出他/她猜测的字符已被纠正，但只是继续并指出我猜错了一个字母!

帮助将不胜感激!!我的问题是我的代码做错了什么？我需要程序来告诉用户他的猜测是对还是错。

我的代码:

import cs1.Keyboard;

public class Hangman {
    public static void main(String args[]) {
        int guessCount = 0;
        int correctGuess = 0;
        boolean foundIt;
        boolean solved;
        char guess, answer;
        String word;
            
        System.out.println("Welcome to HangMan!");
        System.out.println("Please enter a word for the opponent to guess!");
        word = Keyboard.readString();
        while (guessCount <= 6) {
            System.out.println("Please enter any letter A-Z as your guess!");
            guess = Keyboard.readChar();
            for (int i = 0; i < word.length(); i++) {
                if (guess == word.charAt(i)) {
                    System.out.println("You have guessed a correct letter!");
                    correctGuess++;
                    System.out.println("Correct Guess Count: "
                                        + correctGuess);
                    solved = false;
                }
                else if (guess != word.charAt(i)) {
                    System.out.println("Sorry! That is an incorrect guess! " 
                                       + "Please try again!");
                    guessCount++;
                    System.out.println("Guess Count: " + guessCount);
                    solved = false;
                }
            }
            if (correctGuess == word.length()) {
                solved = true;
                System.out.println("Congratulations! " + 
                                   "You have guessed the word!");
            }                   
        }
    }
}

这是我目前所拥有的，这是输出

Welcome to HangMan!
Please enter a word for the opponent to guess!
hello
Please enter any letter A-Z as your guess!
l
Sorry! That is an incorrect guess! Please try again!
Guess Count: 1
Sorry! That is an incorrect guess! Please try again!
Guess Count: 2
You have guessed a correct letter!
Correct Guess Count: 1
You have guessed a correct letter!
Correct Guess Count: 2
Sorry! That is an incorrect guess! Please try again!
Guess Count: 3
Please enter any letter A-Z as your guess!

Answer 1

您将猜测 与String 中的每个字符进行比较，然后针对每个字符显示消息。相反，您应该编写一个方法来返回与输入匹配的字符数(这也处理具有重复字母的单词)。所以，

private static int countOf(String in, char ch) {
    int count = 0;
    for (char c : in.toCharArray()) {
        if (c == ch) {
            count++;
        }
    }
    return count;
}

然后你可以这样调用它，

guess = Keyboard.readChar();
int count = countOf(word, guess);
if (count > 0) {
  System.out.println("You have guessed a correct letter!");
  correctGuess += count;
} else {
  System.out.println("Sorry! That is an inncorrect guess! Please try again!");
}
guessCount++;

编辑 要在没有第二种方法的情况下进行编辑，您可以使用，

guess = Keyboard.readChar();
int count = 0;
for (char c : in.toCharArray()) {
    if (c == guess) {
        count++;
    }
}
if (count > 0) {
  System.out.println("You have guessed a correct letter!");
  correctGuess += count;
} else {
  System.out.println("Sorry! That is an inncorrect guess! Please try again!");
}
guessCount++;

而且，由于您还没有使用 for-each -

char[] chars = in.toCharArray();
for (int i = 0; i < chars.length; i++) {
    if (chars[i] == guess) {
        count++;
    }
}