使用正则表达式解析 Java 字符串

Question

我尝试使用正则表达式解析字符串以从中获取参数。例如:

String: "TestStringpart1 with second test part2"Result should be: String[] {"part1", "part2"}Regexp: "TestString(.*?) with second test (.*?)"

我的测试代码是:

String regexp = "TestString(.*?) with second test (.*?)";String res = "TestStringpart1 with second test part2";Pattern pattern = Pattern.compile(regexp);Matcher matcher = pattern.matcher(res);int i = 0;while(matcher.find()) {    i++;    System.out.println(matcher.group(i));}

但它只输出“part1”有人可以给我提示吗？

谢谢

Answer 1

可能是一些修复正则表达式

String regexp = "TestString(.*?) with second test (.*)";

并更改 println 代码..

if (matcher.find())
    for (int i = 1; i <= matcher.groupCount(); ++i)
        System.out.println(matcher.group(i));