java - 在 Spring MVC 应用程序中启用 Spring Security

Question

我正尝试在我的 spring 应用程序中启用 Spring Security 2.5，但遇到了配置问题。我遵循了几个示例并完成了他们正在做的事情，但我认为我配置的其他内容导致了问题。

这是我的 web.xml:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>onBoardingUI</display-name>


<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
       /WEB-INF/security-context.xml
    </param-value>
</context-param>

<!-- Enables Spring security -->
<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<listener>
    <listener-class>org.apache.commons.fileupload.servlet.FileCleanerCleanup</listener-class>
</listener>

<servlet>
    <servlet-name>testUI</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>testUI</servlet-name>
    <url-pattern>*.html</url-pattern>
</servlet-mapping>

<servlet-mapping>
    <servlet-name>testUI</servlet-name>
    <url-pattern>*.form</url-pattern>
</servlet-mapping>

<welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
</welcome-file-list>

<jsp-config>
    <taglib>
        <taglib-uri>/spring</taglib-uri>
        <taglib-location>/WEB-INF/tld/spring-form.tld</taglib-location>
    </taglib>
</jsp-config>

这是我的 security-context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"    
    xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans
                       http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
                       http://www.springframework.org/schema/security
                       http://www.springframework.org/schema/security/spring-security-2.0.xsd">

<security:global-method-security
    secured-annotations="enabled" />

<security:http auto-config="true">
    <!-- Restrict URLs based on role -->
    <security:intercept-url pattern="/login*"
        access="IS_AUTHENTICATED_ANONYMOUSLY" />
    <security:intercept-url pattern="/logoutSuccess*"
        access="IS_AUTHENTICATED_ANONYMOUSLY" />

    <security:intercept-url pattern="/css/main.css"
        access="IS_AUTHENTICATED_ANONYMOUSLY" />

    <security:intercept-url pattern="/**" access="ROLE_USER" />

    <!-- Override default login and logout pages -->
    <security:form-login login-page="/login.html"
        login-processing-url="/login.html" default-target-url="/index.jsp"
        authentication-failure-url="/login.jsp?login_error=1" />
    <security:logout logout-url="/logout"
        logout-success-url="/login.html" />
</security:http>

<security:authentication-provider>
    <security:jdbc-user-service
        data-source-ref="dataSource" />


</security:authentication-provider>

war 部署失败，这就是日志中的全部内容:

Feb 16, 2010 11:46:29 AM org.apache.catalina.core.StandardContext start
SEVERE: Error listenerStart

这显然是导致我的监听器失败的原因，但我不确定原因。

这是使用 Spring Security 2.5 部署到 Tomcat 6.0.20 和 Spring MVC 2.5。

Answer 1

会不会是您的“数据源”bean 未在 security-context.xml 文件中定义？

还要检查 security-context.xml 在 WAR 中的正确位置 - 根据你的 web.xml 应该在/WEB-INF/security-context.xml - 检查 tomcat 中的分解目录以查看如果它确实存在。

HTH