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php - 验证交易收据时状态 21002

转载 作者:塔克拉玛干 更新时间:2023-11-02 10:13:16 27 4
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我尝试查看所有其他问题,但似乎无法解决此问题。我已经缩小范围,所以来自 https://sandbox.itunes.apple.com/verifyReceipt 的响应只是 {"status":21002}。任何帮助将不胜感激,我已经复制了下面的相关代码。

NSString *completeString = @"http://www.mysite.com/verify.php";

NSURL *urlForValidation = [NSURL URLWithString:completeString];

NSMutableURLRequest *validationRequest = [[NSMutableURLRequest alloc] initWithURL:urlForValidation];

[validationRequest setHTTPMethod:@"POST"];

NSString *strTest = [NSString stringWithFormat:@"receipt=%@", [self createEncodedString:transaction.transactionReceipt]];

[validationRequest setHTTPBody:[NSData dataFromBase64String:strTest]];

NSData *responseData = [NSURLConnection sendSynchronousRequest:validationRequest returningResponse:nil error:nil];

NSString *response = [[NSString alloc] initWithData: responseData encoding: NSUTF8StringEncoding];

NSLog(@"%@", response);

- (NSString*) createEncodedString:(NSData*)data {
static char table[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";

const int size = ((data.length + 2)/3)*4;
uint8_t output[size];

const uint8_t* input = (const uint8_t*)[data bytes];
for (int i = 0; i < data.length; i += 3)
{
int value = 0;
for (int j = i; j < (i + 3); j++)
{
value <<= 8;
if (j < data.length)
value |= (0xFF & input[j]);
}

const int index = (i / 3) * 4;
output[index + 0] = table[(value >> 18) & 0x3F];
output[index + 1] = table[(value >> 12) & 0x3F];
output[index + 2] = (i + 1) < data.length ? table[(value >> 6) & 0x3F] : '=';
output[index + 3] = (i + 2) < data.length ? table[(value >> 0) & 0x3F] : '=';
}

return [[NSString alloc] initWithBytes:output length:size encoding:NSASCIIStringEncoding];
}

最后这是使用的 PHP 代码:

$url = 'https://sandbox.itunes.apple.com/verifyReceipt';

$receipt = "{%s}" % $_POST["receipt"];

$purchase_encoded = base64_encode( $receipt );

$encodedData = json_encode( Array(
'receipt-data' => $purchase_encoded
) );

//Open a Connection using POST method, as it is required to use POST method.
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $encodedData);
$encodedResponse = curl_exec($ch);
curl_close($ch);


//Decode response data using json_decode method to get an object.

echo $encodedResponse;

$response = json_decode( $encodedResponse );

echo $response;

最佳答案

经过大量摆弄后,我终于弄明白了。我认为最大的错误是我设置 HTTP 正文的方式。最终代码如下,希望这可以帮助其他人!

Objective-C :

NSString *completeString = @"http://www.mysite.com/verify.php";

NSURL *urlForValidation = [NSURL URLWithString:completeString];

NSMutableURLRequest *validationRequest = [[NSMutableURLRequest alloc] initWithURL:urlForValidation];

[validationRequest setHTTPMethod:@"POST"];

NSString *strTest = [NSString stringWithFormat:@"receipt=%@", [self base64forData:transaction.transactionReceipt]];

[validationRequest setHTTPBody:[strTest dataUsingEncoding:NSUTF8StringEncoding]];

NSData *responseData = [NSURLConnection sendSynchronousRequest:validationRequest returningResponse:nil error:nil];

NSString *response = [[NSString alloc] initWithData: responseData encoding: NSUTF8StringEncoding];

NSLog(@"%@", response);

PHP:

$url = 'https://sandbox.itunes.apple.com/verifyReceipt';

$encodedData = json_encode( Array(
'receipt-data' => $_POST["receipt"]
) );


//Open a Connection using POST method, as it is required to use POST method.
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $encodedData);
$encodedResponse = curl_exec($ch);
curl_close($ch);

$response = json_decode( $encodedResponse );

/*
echo "Status Code:";

echo $response->{'status'};
*/

if ($response->{'status'} != 0) {
echo "FAIL";
} else {
echo "SUCCESS";
}

关于php - 验证交易收据时状态 21002,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12964728/

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