ios - 无法将类型 'NSDictionary' 的值转换为指定类型 'Dictionary'

Question

为什么这是可能的:

var orderRequestUserValues : Dictionary  = [ "ClientID": "TEST",
                                                 "UserName": "sysadmin",
                                                 "Password": "123456",
                                                 "ModuleID": "StockProcessing",
                                                 "FunctionID": "SetStockActivity",
                                                 "TransmissionFlags": 32,
                                                 "TransmissionMethod": 5
    ]

但这不是:

let userName : String = (dataSourceForUserInfo.last?.UserName)!
let password : String = (dataSourceForUserInfo.last?.Password)!
let clientID : String = (dataSourceForUserInfo.last?.ClientID)!
var orderRequestUserValues : Dictionary  = [  "ClientID": "\(clientID)",
                                              "UserName": "\(userName)",
                                              "Password": "\(password)",
                                              "ModuleID": "StockProcessing",
                                              "FunctionID": "SetStockOrder",
                                              "TransmissionFlags": 32,
                                              "TransmissionMethod": 5


    ]

出现错误:无法将“NSDictionary”类型的值转换为指定类型“Dictionary”

我需要它像这样工作，因为我必须像这样向它附加数据:

orderRequestUserValues.updateValue(requestParameters, forKey: "RequestParameters")

Answer 1

这应该是你想要的

var orderRequestUserValues : [String : Any]  = [
    "ClientID": "TEST",
    "UserName": "sysadmin",
    "Password": "123456",
    "ModuleID": "StockProcessing",
    "FunctionID": "SetStockActivity",
    "TransmissionFlags": 32,
    "TransmissionMethod": 5
]

这也适用于字符串插值:

var orderRequestUserValues : [String : Any]  = [
    "ClientID": "\(clientID)",
    "UserName": "\(userName)",
    "Password": "\(password)",
    "ModuleID": "StockProcessing",
    "FunctionID": "SetStockOrder",
    "TransmissionFlags": 32,
    "TransmissionMethod": 5
]

---

还要注意，如果字典是不可变的，您可以使用 let 而不是 var。