ios - 当我的 wifi 连接到我的 iPhone 手机时打开一些链接

Question

我们需要在 iPhone 手机中连接 wifi 时。我们需要在浏览器中自动打开应用程序故事。即我们有 4 个 wifi 的 Himansu、点击、投票、热点。我们需要当 wifi 连接 Humans 后，它会重定向到下面的链接

https://itunes.apple.com/in/app/facebook/id284882215?mt=8

请给我任何想法。首先告诉我这可能与否

Answer 1

使用苹果提供的代码here

Reachability *reach = [Reachability reachabilityForInternetConnection];
[reach startNotifier];

NetworkStatus status = [reach currentReachabilityStatus];

if(status == NotReachable) 
{
    //No internet
}
else if (status == ReachableViaWiFi)
{
    //WiFi
         [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://itunes.apple.com/in/app/facebook/id284882215?mt=8"]];

}
else if (status == ReachableViaWWAN) 
{
    //3G
     [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://itunes.apple.com/in/app/facebook/id284882215?mt=8"]];
}

获取Wifi网络名称

第 1 步:

导入框架#import <SystemConfiguration/CaptiveNetwork.h>

步骤-2

implement the method in 

     CFArrayRef myArray = CNCopySupportedInterfaces();
    CFDictionaryRef myDict =   CNCopyCurrentNetworkInfo(CFArrayGetValueAtIndex(myArray, 0));

   NSLog(@"Connected at:%@",myDict);
   NSDictionary *myDictionary = (__bridge_transfer   NSDictionary*)myDict;

   NSString *  SSID = [myDictionary objectForKey:@"SSID"];
   NSLog(@"bssid is %@", SSID);

  // your console output is just like 
   SSID = "Eqra'aOrange";

步骤 - 3

  now you check your condition 

    if ([SSID isEqualToString:@"Himansu"])
    {
      // customize your code
     }
    else
     {
     // do your stuff
    }