ios - 如何比较两个数字并选择最小的数字继续执行？

Question

假设 number = 0 和 otherNumber = 10。循环将执行。但是如果 number = 10 和 otherNumber = 0 怎么办。我希望编译器选择最小的数字并使用它继续。

我目前的代码在这里:

- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
    if (number <= otherNumber) {
        NSMutableString *indices = [NSMutableString stringWithCapacity:1];
        for (NSInteger i= number; i <= otherNumber; i++) {
            [indices appendFormat:@"%d", i];
        }
    } else {
        NSMutableString *indices = [NSMutableString stringWithCapacity:1];
        for (NSInteger i= otherNumber; i <= number; i++) {
            [indices appendFormat:@"%d", i];
        }
    }
    return @"%@", indices;
}

Answer 1

一个简单的解决方法是将 indices 的声明移到条件之外:

- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
    NSMutableString *indices = [NSMutableString stringWithCapacity:1];
    if (number <= otherNumber) {
        for (NSInteger i= number; i <= otherNumber; i++) {
            [indices appendFormat:@"%d", i];
        }
    } else {
        for (NSInteger i= otherNumber; i <= number; i++) {
            [indices appendFormat:@"%d", i];
        }
    }
    return indices;
}

你可以像这样进一步统一你的:

- (NSString *) stringWithNumbersBetweenNumber:(NSInteger)number andOtherNumber: (NSInteger)otherNumber {
    NSInteger from, to;
    if (number <= otherNumber) {
        from = number;
        to = otherNumber;
    } else {
        from = otherNumber;
        to = number;
    }
    NSMutableString *indices = [NSMutableString stringWithCapacity:1];
    for (NSInteger i= from; i <= tp; i++) {
        [indices appendFormat:@"%d", i];
    }
    return indices;
}