ios - 将 UIImage 转换为 8 位

Question

我希望将 UIImage 转换为 8 位。我试图这样做，但我不确定我是否做对了，因为稍后当我尝试使用图像处理库 leptonica 时收到一条消息，指出它不是 8 位。任何人都可以告诉我我是否正确地执行此操作或如何执行此操作的代码？

谢谢!

代码

 CGImageRef myCGImage = image.CGImage;
 CFDataRef data = CGDataProviderCopyData(CGImageGetDataProvider(myCGImage));
 const UInt8 *imageData = CFDataGetBytePtr(data);

Answer 1

以下代码适用于没有 alpha channel 的图像:

    CGImageRef c = [[UIImage imageNamed:@"100_3077"] CGImage];

    size_t bitsPerPixel = CGImageGetBitsPerPixel(c);
    size_t bitsPerComponent = CGImageGetBitsPerComponent(c);
    size_t width = CGImageGetWidth(c);
    size_t height = CGImageGetHeight(c);

    CGImageAlphaInfo a = CGImageGetAlphaInfo(c);

    NSAssert(bitsPerPixel == 32 && bitsPerComponent == 8 && a == kCGImageAlphaNoneSkipLast, @"unsupported image type supplied");

    CGContextRef targetImage = CGBitmapContextCreate(NULL, width, height, 8, 1 * CGImageGetWidth(c), CGColorSpaceCreateDeviceGray(), kCGImageAlphaNone);

    UInt32 *sourceData = (UInt32*)[((__bridge_transfer NSData*) CGDataProviderCopyData(CGImageGetDataProvider(c))) bytes];
    UInt32 *sourceDataPtr;

    UInt8 *targetData = CGBitmapContextGetData(targetImage);

    UInt8 r,g,b;
    uint offset;
    for (uint y = 0; y < height; y++)
    {
        for (uint x = 0; x < width; x++)
        {
            offset = y * width + x;

            if (offset+2 < width * height)
            {
                sourceDataPtr = &sourceData[y * width + x];

                r = sourceDataPtr[0+0];
                g = sourceDataPtr[0+1];
                b = sourceDataPtr[0+2];

                targetData[y * width + x] = (r+g+b) / 3;
            }
        }
    }

    CGImageRef newImageRef = CGBitmapContextCreateImage(targetImage);
    UIImage *newImage = [UIImage imageWithCGImage:newImageRef];

    CGContextRelease(targetImage);
    CGImageRelease(newImageRef);

使用这段代码，我将 rgb 图像转换为灰度图像:

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