ios - 我想处理 ios 中的调用状态

Question

我想知道电话的状态是已拨、接通还是断开...

我尝试了自己，但我无法获取状态。

NSString *phoneNumber = [@"telprompt://" stringByAppendingString:@"9723539389"];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

CTCallCenter *callCenter = [[CTCallCenter alloc] init];
callCenter.callEventHandler=^(CTCall* call)
{
    if(CTCallStateDialing)
    {
        NSLog(@"Dialing");
    }
    if(CTCallStateConnected)
    {
        NSLog(@"Connected");
    }
    if(CTCallStateDisconnected)
    {
        NSLog(@"Disconnected");
    }
};

但问题是 CTCallCenter block 从未调用过......我目前在 iOS 7 中工作

Answer 1

您应该检查 CTCall 的 callState 属性以捕获它

Use a cellular call’s CTCall object to obtain an identifier for the call and to determine the call’s state.

 extern NSString const *CTCallStateDialing;
 extern NSString const *CTCallStateIncoming;
 extern NSString const *CTCallStateConnected;
 extern NSString const *CTCallStateDisconnected;

是字符串常量。你的 for 循环没有意义。

NSString *phoneNumber = [@"telprompt://" stringByAppendingString:@"9723539389"];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

self.callCenter = [[CTCallCenter alloc] init];

[callCenter setCallEventHandler:^(CTCall* call)
{
    if ([call.callState isEqualToString: CTCallStateConnected])
    {
        NSLog(@"Connected");
    }
    else if ([call.callState isEqualToString: CTCallStateDialing])
    {
        NSLog(@"Dialing");
    }
    else if ([call.callState isEqualToString: CTCallStateDisconnected])
    {
        NSLog(@"Disconnected");

    } else if ([call.callState isEqualToString: CTCallStateIncoming])
    {
        NSLog(@"Incoming");
    }

}];

注意:

  @property(nonatomic, strong) CTCallCenter *callCenter;

应在 Appdelegate 中声明并保留它。否则它将被视为局部变量并在循环结束后立即释放

更新:

回答“callCenter 是在 appdelegate 中声明的，我如何将它与自己一起使用？当 [] 添加到该 block 时，它会显示错误等于“预期的']'“”

用这些行替换 self.callCenter

   YourApplicationDelegateClass *appDel =(YourApplicationDelegateClass*)[UIApplication sharedApplication].delegate;

   appDel.callCenter =  [[CTCallCenter alloc] init];