ios - 如何在 SpriteKit 中添加高亮按钮？

Question

我知道如何在 SpriteKit 中添加 Button。

我已经完成了 SKSpriteNode。但是我不知道如何添加像 UIButton 这样的高亮按钮。

我的意思是，当我按下 SKSpriteNode(Button) 时，我想显示突出显示的图像，例如来自 UIKit 的 UIButton。

我该怎么做？

这是我的代码，用于 Button 和 SKSpriteNode。

self.playButton = [SKSpriteNode spriteNodeWithImageNamed:@"playButton.png"];
self.playButton.position = CGPointMake(self.frame.origin.x + 400, 100);
self.playButton.name = @"playButton";
self.playButton.zPosition = 2;
[self addChild:self.playButton];

Answer 1

我试过了，得到了你想要的东西，

  BOOL isMySpriteNodeTouched = NO;
 mySprite = [[SKSpriteNode alloc]initWithImageNamed:@"ball"];
 mySprite.position = CGPointMake(self.size.width/2.0f, self.size.height/2.0f);
 mySprite.name = @"mySprite";
[self addChild:mySprite];


 -(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event

{
    for (UITouch *touch in touches)
      {
           CGPoint touchPoint = [touch locationInNode:self];
           SKNode *localNode = [[SKNode alloc]init];
           localNode = [self nodeAtPoint:touchPoint];

           if ([localNode.name isEqualToString:mySprite.name])
          {
               mySprite.texture = [SKTexture textureWithImage:[UIImage imageNamed:@"highlightedBall"]];
             isMySpriteNodeTouched = YES;
          }
 }



-(void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
   {
     if(isMySpriteNodeTouched)
       {
         isMySpriteNodeTouched = !isMySpriteNodeTouched;
         mysprite.texture = [SKTexture textureWithImage:[UIImage imageNamed:@"ball"]];
        } 
   }