gpt4 book ai didi

ios - 从 NSDictionary 获取值

转载 作者:塔克拉玛干 更新时间:2023-11-02 09:05:44 24 4
gpt4 key购买 nike

大家好,我是 iOS 开发的新手。我想获得响应并将这些值添加到变量。

我试过了,但我得到的响应低于此值。我不明白为什么此响应中有斜线。

@"[{\"VisitorID\":\"2864983a-e26b-441a-aedf-84e2a1770b8e\",\"ProfileID\":\"69c02265-abca-4716-8a2f-ac5d642f876a\",\"CompanyID\":null,\"VisitorName\":\"kanasalingam\",\"OperatorName\":\"baman\",\"Image\":null,\"isocode\":\"lk\",\"CurrentOperator\":[\"69c02265-abca-4716-8a2f-ac5d642f876a\"]},{\"VisitorID\":\"133bc108-b3bf-468a-9397-e1b0dba449db\",\"ProfileID\":\"69c02265-abca-4716-8a2f-ac5d642f876a\",\"CompanyID\":null,\"VisitorName\":\"kumar\",\"OperatorName\":\"baman\",\"Image\":null,\"isocode\":\"lk\",\"CurrentOperator\":[\"69c02265-abca-4716-8a2f-ac5d642f876a\"]}]"

我试过这个:

- (void) sendOtherActiveChats:(NSDictionary *) chatDetails{
NSLog(@"inside sendOtherActiveChats");
NSLog(@"otherDetails Dictionary : %@ ", chatDetails);

NSString *VisitorID = [chatDetails objectForKey:@"VisitorID"];
NSString *ProfileID = [chatDetails objectForKey:@"ProfileID"];
NSString *CompanyID = [chatDetails objectForKey:@"CompanyID"];
NSString *VisitorName = [chatDetails objectForKey:@"VisitorName"];
NSString *OperatorName = [chatDetails objectForKey:@"OperatorName"];
NSString *isocode = [chatDetails objectForKey:@"isocode"];

NSLog(@"------------------------Other Active Chats -----------------------------------");
NSLog(@"VisitorID : %@" , VisitorID);
NSLog(@"ProfileID : %@" , ProfileID);
NSLog(@"CompanyID : %@" , CompanyID);
NSLog(@"VisitorName : %@" , VisitorName);
NSLog(@"OperatorName : %@" , OperatorName);
NSLog(@"countryCode: %@" , isocode);
NSLog(@"------------------------------------------------------------------------------");

}

谁能帮我从这个字符串中获取值?

最佳答案

您正在获得字典数组作为响应,但您的响应是字符串形式的,因此您可以使用 NSJSONSerialization 将其转换为 NSArray,就像这样将您的响应字符串转换为NSData,然后使用该数据和 JSONObjectWithData: 从中获取数组。

NSString *jsonString = @"[{\"VisitorID\":\"2864983a-e26b-441a-aedf-84e2a1770b8e\",\"ProfileID\":\"69c02265-abca-4716-8a2f-ac5d642f876a\",\"CompanyID\":null,\"VisitorName\":\"kanasalingam\",\"OperatorName\":\"baman\",\"Image\":null,\"isocode\":\"lk\",\"CurrentOperator\":[\"69c02265-abca-4716-8a2f-ac5d642f876a\"]},{\"VisitorID\":\"133bc108-b3bf-468a-9397-e1b0dba449db\",\"ProfileID\":\"69c02265-abca-4716-8a2f-ac5d642f876a\",\"CompanyID\":null,\"VisitorName\":\"kumar\",\"OperatorName\":\"baman\",\"Image\":null,\"isocode\":\"lk\",\"CurrentOperator\":[\"69c02265-abca-4716-8a2f-ac5d642f876a\"]}]";
NSData *data = [jsonString dataUsingEncoding:NSUTF8StringEncoding];

NSError *e;
NSMutableArray *jsonArray = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers error:&e];

现在遍历数组并从中访问每个字典。

for (NSDictionary *dic in jsonArray) {
NSLog(@"%@",[dic objectForKey:@"VisitorID"]);
... and so on.
}

关于ios - 从 NSDictionary 获取值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41460099/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com