android - 按 Enter 键时搜索 Activity 未启动

Question

按 enter 键时搜索 Activity 未启动。搜索 View 在操作栏上显示得很好。但是当我输入搜索查询并按回车键时

AndroidManifest.xml

<?xml version="1.0" encoding="utf-8"?>
   <manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.punit.rateit"
android:versionCode="1"
android:versionName="1.0" >

<uses-sdk
    android:minSdkVersion="11"
    android:targetSdkVersion="17" />
<uses-permission android:name="android.permission.INTERNET"/>

<application
    android:allowBackup="true"
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/AppTheme"

    >
    <activity
        android:name="com.punit.rateit.MainActivity"
        android:label="@string/app_name" >

        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

    <activity android:theme="@style/Theme.AppCompat.Light"
              android:name=".SearchPageActivity">
          <meta-data android:name="android.app.default_searchable" android:value=".SearchResultsActivity" /> 
      <intent-filter>
         <action android:name="android.intent.action.SearchPage" />
      </intent-filter>
    </activity>

   <activity android:name="com.punit.rateit.SearchResultsActivity"   android:launchMode="singleTop" >
  <intent-filter>
    <action android:name="android.intent.action.SEARCH" />
     <meta-data android:name="android.app.searchable"
               android:resource="@xml/searchable"/>
    </intent-filter>
   </activity>       

    </application>

 </manifest>

这是 Menu.xml

<menu xmlns:android="http://schemas.android.com/apk/res/android"
  xmlns:com.punit.rateit="http://schemas.android.com/apk/res-auto" >
<!-- Search, should appear as action button -->
<item android:id="@+id/search"
      android:icon="@drawable/ic_search"
      android:title="@string/action_search"
      com.punit.rateit:actionViewClass="android.widget.SearchView"
       com.punit.rateit:showAsAction="ifRoom"

       />

   </menu>

显示操作栏的 Activity 。

     public boolean onCreateOptionsMenu(Menu menu) {

     MenuInflater inflater = getMenuInflater();
        inflater.inflate(R.menu.menu,menu);
     SearchManager searchManager =
             (SearchManager) getSystemService(Context.SEARCH_SERVICE);

      SearchView searchView =
              (SearchView) menu.findItem(R.id.search).getActionView();

      searchView.setSearchableInfo(searchManager.getSearchableInfo(getComponentName()));
      searchView.setIconifiedByDefault(false);
      searchView.setSubmitButtonEnabled (true); 
     return super.onCreateOptionsMenu(menu);
 }

SearchResult Activity 应该是按下搜索提交按钮时调用的 Activity

public class SearchResultsActivity extends Activity {


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    Log.d("search", "search triggered");
    setContentView(R.layout.searchpage);

    handleIntent(getIntent());
}
@Override
protected void onNewIntent(Intent intent) {
    Log.d("search", "search triggered");
    setIntent(intent);
    handleIntent(intent);
}
private void handleIntent(Intent intent)
{
     if (Intent.ACTION_SEARCH.equals(intent.getAction())) {
            String query = intent.getStringExtra(SearchManager.QUERY);
            Log.d("search", query);
}
  }

 @Override
 public boolean onSearchRequested() {

     Log.d("search", "search triggered");

     return false;  // don't go ahead and show the search box
 }

Answer 1

经过长时间的研究，我分析了一些东西

searchView.setSearchableInfo( searchManager.getSearchableInfo(new 
ComponentName(this,SearchResultsActivity.class)));

这里的 activity.class 是您要传递搜索查询的可搜索 Activity 的名称。