java - 如何得到如下格式化输出？

Question

我编写了代码以获得以下格式化输出，但是当我输入两位数的行数时，输出格式发生了变化。为什么？我该如何解决这个问题？

      1
    1 2 1
  1 2 3 2 1
1 2 3 4 3 2 1

这是我的代码:

import java.util.*;
class PTri {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter the no. of rows for which " +
                "triangle has to be constructed");
        int numrow = sc.nextInt();
        for (int i = 1; i <= numrow; i++) {
            for (int j = 1; j <= numrow - i; j++) {
                System.out.print("  ");
            }
            for (int k = 1; k < i * 2; k++) {
                System.out.print(Math.min(k, i * 2 - k) + " ");
            }
            System.out.println();
        }
    }
}

Answer 1

因为两位数的值会改变整个架构，集合会右移一位。所以你可以这样设置条件。我在数字之间添加了一个额外的空格以提高可见性。

import java.util.*;
class PTri {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter the no. of rows for which " +
                "triangle has to be constructed");
        int numrow = sc.nextInt();
        for (int i = 1; i <= numrow; i++) {
            for (int j = 1; j <= (numrow - i); j++) {
                System.out.print("    ");
            }
            for (int k = 1; k < i * 2; k++) {
                int temp = Math.min(k, i * 2 - k);

                if (temp > 9) {
                    System.out.print(temp + "  ");
                } else {
                    System.out.print(temp + "   ");
                }
            }
            System.out.println();
        }
    }
}