java - 同时使用 WASD 和方向键

Question

我正在使用 Processing(在 Java 上运行)开发一款两人游戏。一个用户将使用 WASD 键控制他的角色，另一个用户将使用箭头键控制移动。我遇到的问题是，在按下箭头时使用 keyPressed 会否定 WASD，反之亦然。我已经弄乱它​​很长时间了。有没有人知道解决方法或注意到我做错了什么？

//global variables
int wide = 600; //canvas width
int tall = 600; //canvas height
int s = 50; //player size
float speed = 2.5; //player movement speed

//colors
int redColor = #CB4646; //player 1 color
int blueColor = #4652CB; //player 2 color
int backgroundColor = #DBE3B3; //background color
float player1X = 600/3-s;  //HOW COME width/3 DOESN'T WORK??????????
float player2X = 600*2/3;
float playerY = 600/2-(s/2);

//players
Player player1 = new Player(player1X, playerY, s, speed, "wasd", redColor); //player 1
Player player2 = new Player(player2X, playerY, s, speed, "arrows", blueColor); //player 2

//setup
void setup(){
  background(backgroundColor);
  size(wide, tall);
  smooth();
  println(player2.controls);
}

//draw
void draw(){
  background(backgroundColor);
  player1.usePlayer();
  player2.usePlayer();
}

class Player{

   //class variables
   float x; // x position
   float y; // y position
   int s; //size
   float speed; //speed
   String controls; //controls
   int colors; //player color
   char keyControls [] = new char [4];

   //construct
   Player(float tempX, float tempY, int tempS , float tempSpeed, String tempControls, int tempColors){
     x = tempX; 
     y = tempY; 
     s = tempS; 
     speed = tempSpeed; 
     controls = tempControls; 
     colors = tempColors; 
   }

   void usePlayer(){

     // draw player
     fill(colors);
     rect(x, y, s, s);

     //move player
     keyPressed();

     //wraparound
     boundaries();

   }

   void keyPressed(){

     //sets controls for wasd
     if(controls == "wasd"){ 
          if(key == 'w' || key == 'W'){ 
            y -= speed; //move forwards
          }
          if(key == 's' || key == 'S'){
            y += speed; //move backwards
          }
            if(key == 'd' || key == 'D'){
            x += speed; //move right
          }
          if(key == 'a' || key == 'A'){
            x -= speed; //move left
          }
         }

      //sets controls for arrows 
      if(controls == "arrows"){ 
        if(key == CODED){
          if(keyCode == UP){ 
            y -= speed; //move forwards
          }
          if(keyCode == DOWN){
            y += speed; //move backwards
          }
            if(keyCode == RIGHT){
            x += speed; //move right
          }
          if(keyCode == LEFT){
            x -= speed; //move left
          }
         }  
        }  
       }

    //pacman style wraparound
    void boundaries(){
     if(x == width) x = 2;
     if(y == height) y = 2;
     if(x == 0) x = width-s;
     if(y == 0) y = height-s;
    }
}

Answer 1

独立跟踪您的 key ，不要依赖事件全局变量。

boolean[] keys = new int[255];

void keyPressed() {
  keys[keyCode] = true;
}

void keyReleased() {
  keys[keyCode] = false;
}

void draw() {
  updatePlayers();
  drawStuff();
}

void updatePlayers() {
  if(keys[LEFT]) { p1.move(-1,0); }
  if(keys[RIGHT]) { p1.move(1,0); }
  if(keys[UP]) { p1.move(0,-1); }
  if(keys[DOWN]) { p1.move(0,1); }

  if(keys['a']) { p2.move(-1,0); }
  if(keys['d']) { p2.move(1,0); }
  if(keys['w']) { p2.move(0,-1); }
  if(keys['s']) { p2.move(0,1); }
}

请注意，这必须是一系列 if 语句，因为您要处理所有按下的键。如果有人握住左手和右手，p1 将左右移动。

另请注意，此示例代码不会过滤您为特殊键获得的高于 255 的代码，因此您可能希望在事件处理程序的开头放置一个“if(keyCode>255) return” .